To find the even two-digit numbers where the sum of the digits is 5, we need to consider the possible combinations of digits. The digits that sum up to 5 are (1,4) and (2,3). For the numbers to be even, the units digit must be 4, so the possible numbers are 14 and 34. Therefore, there are 2 even two-digit numbers where the sum of the digits is 5.
There are 5760 such numbers.
500
6*6*3 = 108 numbers.
There are 5460 five digit numbers with a digit sum of 22.
5 x 10 x 5 = 250 different numbers, assuming there is no limit to each digits' use.
There are 5760 such numbers.
There are 41 of them.
500
25 of them
There are 500000 such numbers.
To form three-digit even numbers from the set {2, 3, 5, 6, 7}, we can use the digits 2 or 6 as the last digit (to ensure the number is even). For each case, we can choose the first two digits from the remaining four digits. For three-digit numbers, there are 2 options for the last digit and (4 \times 3 = 12) combinations for the first two digits, resulting in (2 \times 12 = 24) even numbers. For four-digit even numbers, we again have 2 options for the last digit. The first three digits can be selected from the remaining four digits, giving us (4 \times 3 \times 2 = 24) combinations for each last digit. Thus, there are (2 \times 24 = 48) even four-digit numbers. In total, there are (24 + 48 = 72) three-digit and four-digit even numbers that can be formed from the set.
None, because you do not have three even digits. None, because you do not have three even digits. None, because you do not have three even digits. None, because you do not have three even digits.
17
With 123 digits you can make 123 one-digit numbers.
6*6*3 = 108 numbers.
There are 5460 five digit numbers with a digit sum of 22.
More than one
The second digit can be 2,4,6, or 8. There are 4 ways of choosing the second digit. The first digit can be chosen from the remaining 8 digits. 8x4 = 32 numbers. Here, it is assumed that the numbers do not repeat
The numbers from 1 to 39 include both single-digit and double-digit numbers. There are 9 single-digit numbers (1 to 9) and 30 double-digit numbers (10 to 39). Therefore, the total number of digits is 9 (from single-digit numbers) + 60 (from double-digit numbers, as each has 2 digits) = 69 digits in total.
18
27 three digit numbers from the digits 3, 5, 7 including repetitions.
The final digit must be a 2 to form an even number. The first digit may be any of three remaining digits (1, 3, 5) while the second digit may be any of the two remaining digits. All together, that makes 3*2 = 6 distinct even numbers.
Assuming the question refers to the digits 1, 2, ... , 9 the answer is 1344 numbers.
The two-digit numbers with both digits even are formed using the even digits 0, 2, 4, 6, and 8. However, since the first digit (the tens place) cannot be 0, the possible choices for the first digit are 2, 4, 6, and 8 (4 options). The second digit (the units place) can be 0, 2, 4, 6, or 8 (5 options). Therefore, the total number of two-digit numbers with both digits even is (4 \times 5 = 20).
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.