To determine which number is divisible by 3, 6, and 9, we need to check if the sum of the digits of each number is divisible by 3.
For 369: 3+6+9 = 18, which is divisible by 3, 6, and 9. Therefore, 369 is divisible by 3, 6, and 9.
For 246: 2+4+6 = 12, which is divisible by 3 but not by 6 or 9. Therefore, 246 is divisible by 3 but not by 6 or 9.
For 468: 4+6+8 = 18, which is divisible by 3, 6, and 9. Therefore, 468 is divisible by 3, 6, and 9.
For 429: 4+2+9 = 15, which is divisible by 3 but not by 6 or 9. Therefore, 429 is divisible by 3 but not by 6 or 9.
Therefore, the numbers 369 and 468 are divisible by 3, 6, and 9.
Any of the infinite set of numbers of the form k*369 where k is any integer. For example 36900369000000369
369/3 = 123
No. It is only divisible by: 1 3 9 41 123 and 369.
No.
All Factors of 369:1, 3, 9, 41, 123, 369
No, it is divisible by 3 and several other numbers.
It is: 193-246+369 = 316
369 is divisible by 1, 3, 9, 41, 123, and 369.
By the multiples of 123 (which are infinite), including these: 123, 246, 369, 492, 615, 738, 861, 984, 1107 . . .
Any of the infinite set of numbers of the form k*369 where k is any integer. For example 36900369000000369
All the numbers are divisible by: 9
No, 369 is divisible by 3.
369/3 = 123
No
No. It is only divisible by: 1 3 9 41 123 and 369.
For a start, 738 is. Then there is 2*738 = 1476.
No.