I can't shake the nagging feeling that I'm supposed to get
some kind of a list of choices along with this question.
To determine if the point (5, 6) is on the graph of the equation ( y - 2x + 5 = 0 ), we can substitute ( x = 5 ) into the equation. This gives us ( y - 2(5) + 5 = 0 ) or ( y - 10 + 5 = 0 ), which simplifies to ( y = 5 ). Since the point has coordinates (5, 6), and our calculation gives us ( y = 5 ), the point (5, 6) is not on the graph of the equation.
If x equals a constant number, the graph will be a vertical line. For example, the graph of x = 5 would be a vertical line that goes through the point (5,0). x equals 5 on every point along this lines.
It seems there may be a typo in your question, as "f(x)5x" is not a standard mathematical expression. If you meant to ask about the function f(x) = 5x, then a point on this graph can be determined by substituting any value for x. For example, if x = 1, then f(1) = 5(1) = 5, so the point (1, 5) is on the graph.
It seems there may be a typo in your function notation. If you meant to express the function as ( f(x) = -2(x^3) + 5 ), you can find a point on the graph by choosing a value for ( x ). For example, if ( x = 0 ), then ( f(0) = -2(0^3) + 5 = 5 ). Thus, the point ( (0, 5) ) lies on the graph of the function.
The figures are exactly the same, but every point on the first graph is exactly 13 below the corresponding point on the second one.
5/4 is a just a single point on a numbered line. That point is its graph.
10,10
10,0
To determine if the point (5, 6) is on the graph of the equation ( y - 2x + 5 = 0 ), we can substitute ( x = 5 ) into the equation. This gives us ( y - 2(5) + 5 = 0 ) or ( y - 10 + 5 = 0 ), which simplifies to ( y = 5 ). Since the point has coordinates (5, 6), and our calculation gives us ( y = 5 ), the point (5, 6) is not on the graph of the equation.
If x equals a constant number, the graph will be a vertical line. For example, the graph of x = 5 would be a vertical line that goes through the point (5,0). x equals 5 on every point along this lines.
It seems there may be a typo in your question, as "f(x)5x" is not a standard mathematical expression. If you meant to ask about the function f(x) = 5x, then a point on this graph can be determined by substituting any value for x. For example, if x = 1, then f(1) = 5(1) = 5, so the point (1, 5) is on the graph.
It seems there may be a typo in your function notation. If you meant to express the function as ( f(x) = -2(x^3) + 5 ), you can find a point on the graph by choosing a value for ( x ). For example, if ( x = 0 ), then ( f(0) = -2(0^3) + 5 = 5 ). Thus, the point ( (0, 5) ) lies on the graph of the function.
The figures are exactly the same, but every point on the first graph is exactly 13 below the corresponding point on the second one.
1) You write the equation in slope-intercept form, if it isn't in that form already. 2) An easy way to graph it is to start with the y-intercept. For example, if the intercept is +5, you graph the point (0, 5). Then you add an additional point, according to the slope. For example, if the slope is 1/2, you go 2 units to the right, and one up, and graph a point there.
multiply each coordinate by -1For Example:Starting coordinates ---> (5,3)Multiply by -1 ---> (5,3) * -1Final answer ---> (-5,-3)
The graph of x=5 would simply be a vertical line that passes through the x-intercept of 5. Since x=5, any single point on the graph would have the x coordinate of 5, because no matter what, x=5. This is why It is a vertical line through (5,0).
5% is 5/100. So you can divide by 100 by moving the decimal point 2 places to the left and then multiply by 5, or you can multiply by 5 first and then move the decimal point. Or you can divide by 2 and move the decimal point 1 place to the left. Either way, I get 9.525.