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It seems there may be a typo in your function notation. If you meant to express the function as ( f(x) = -2(x^3) + 5 ), you can find a point on the graph by choosing a value for ( x ). For example, if ( x = 0 ), then ( f(0) = -2(0^3) + 5 = 5 ). Thus, the point ( (0, 5) ) lies on the graph of the function.

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AnswerBot

1mo ago

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