Infinitely many points lies on this line (that's what a line is) but, not ALL points lie on this line.
Assuming it's not complex analysis (If you don't know of a phrase, you are not doing it, that's my moto).
Take the real plane with the usual x-axis and y-axis. The set of all points can be expressed as {(x, y) : 3x + 6y = 2, x, y are REAL} or any x and y satisfies 3x + 6y = 2 (there are many such points)
For simplicity, without loss of generality, we can fix an arbitrary x, and rearrange the equation so y = (2 - 3x)/6. So you can also write the set of points as {(x, (2 - 3x)/6 : x is real}
Similar, you can write it terms of y {((2 - 6y)/3, y) : y is real}
The points are (-0.25, 0) and (0, 1)
5
4.9
6.2
12.9
The points are (-0.25, 0) and (0, 1)
5
There are infinitely many points on the line. One such is (-6, 3.33...)
Assuming the line is 3x - 2y = 4, the point (1, -1/2) lies in it.
4.9
6.2
12.9
It is every point in the plane that lies on the straight line defined by the equation -5x + 4y = -3. Since there are an infinite number of points on that line, there is no point in trying to list them.
Depending on the domain of x, there are infinitely many points on the line. Select any value for x, calculate y = -2 - 3x. Then the point (x, -2 - 3x) is on the line.
8.3
16.1
That's a sphere.