Assuming the line is 3x - 2y = 4, the point (1, -1/2) lies in it.
(5, -8)
Which of the following is the point-slope equation of the line with a slope equals -4 and a point of -2 3?
No because a defined straight line has 2 end points.
Substitute the x coordinate into the equation for x and calculate y. If the formla gives the same y value as the coordinates, the point is on the line. If it is diffent, it is not on the line.
The points are (-0.25, 0) and (0, 1)
5
Assuming the line is 3x - 2y = 4, the point (1, -1/2) lies in it.
Depending on the domain of x, there are infinitely many points on the line. Select any value for x, calculate y = -2 - 3x. Then the point (x, -2 - 3x) is on the line.
It is every point in the plane that lies on the straight line defined by the equation -5x + 4y = -3. Since there are an infinite number of points on that line, there is no point in trying to list them.
(6,5)
A point lies on a line if the coordinates of the point satisfy the equation of the line.
(4,1)
(5, -8)
(2, 11)
An infinite number of points lie on that line. One such would be (40, 65).
They define one plane. A line is defined by two points, and it takes three points to define a plane, so two points on the line, and one more point not on the line equals one plane.