Any polyhedron other than a pyramid.
Prism.
Any member of the prism family.
Euler.
The number of vertices and faces is 2 more than the number of Edges according to Euler's formula. So a gemstone with 22 edges must have a total of 24 faces and vertices.
Any polyhedron other than a pyramid.
Prism.
Hexahedron
octahedron
A dodecahedron
For all polyhedra: vertices + faces = edges + 2 The given fact is: edges = vertices + 10 → vertices + faces = vertices + 10 + 2 → faces = 12
Tetrahedron- (4 faces, 4 vertices) Octahedron- (8 faces, 6 vertices) Cube- (6 faces, 8 vertices)
Any member of the prism family.
Euler.
The number of vertices and faces is 2 more than the number of Edges according to Euler's formula. So a gemstone with 22 edges must have a total of 24 faces and vertices.
According to the Euler characteristic which applies to all simply connected polyhedra,# edges + 2 = # vertices + # faces. So the answer is 2 fewer.
You can find a polyhedron with any number greater than 4 of vertices or faces. However, a torus, ellipsoid, sphere, paraboloid, hyperboloid are all standard shapes with no vertices. Cylinders, too, have no vertices. And there are many completely random shapes - a lump of putty, for example, which will have no vertex.