Any polyhedron other than a pyramid.
Prism.
Any member of the prism family.
Euler.
The number of vertices and faces is 2 more than the number of Edges according to Euler's formula. So a gemstone with 22 edges must have a total of 24 faces and vertices.
Any polyhedron other than a pyramid.
Oh, dude, that's an easy one. A shape like a cube has more faces than vertices. Like, think about it, a cube has 6 faces but only 8 vertices. So, yeah, the faces totally outnumber the vertices in that situation.
Prism.
Hexahedron
octahedron
A dodecahedron
Tetrahedron- (4 faces, 4 vertices) Octahedron- (8 faces, 6 vertices) Cube- (6 faces, 8 vertices)
Oh, dude, it's like a math riddle! So, if a polyhedron has 10 more edges than vertices, we can use Euler's formula: Faces + Vertices - Edges = 2. Since we know the relationship between edges and vertices, we can substitute that in and solve for faces. So, it would have 22 faces. Math can be fun... sometimes.
Any member of the prism family.
Euler.
The number of vertices and faces is 2 more than the number of Edges according to Euler's formula. So a gemstone with 22 edges must have a total of 24 faces and vertices.
According to the Euler characteristic which applies to all simply connected polyhedra,# edges + 2 = # vertices + # faces. So the answer is 2 fewer.