An infinite number of solutions exist. A rational number just means it can be expressed as a whole number, decimal, or fraction. So you could have 1/2 X 2 or 1/3 X 3 or 2/3 X 3/2 or 1.5 X (2/3). Or of course you could have 1 X 1. Or if you like you can use two negative numbers, like -1 X -1 or -1/2 X -2.
Yes.2 and 0.5 are both rational. But 2^0.5, which is sqrt(2), is irrational.
The way in which the binary functions, addition and multiplication, are defined on the set of rational numbers ensures that the set is closed under these two operations.
11*27 = 297
Uhh... okay then... 500 and 2.
There are infinitely many rational numbers between any two rational numbers. And the cardinality of irrational numbers between any two rational numbers is even greater.
You get a product which can be rational or irrational.
It must be a generalised rational number. Otherwise, if you select a rational number to multiply, then you will only prove it for that number.
The fact that they can be expressed as a ratio of two whole numbers (with the denominator being non-zero).
The two numbers multiplied are 12*12, 1*144
The product of two rational numbers is a rational number. All decimal numbers that terminate or end with a repeating sequence of digits are rational numbers. As both 0.54732814 (as written) and 0.5 are terminating decimals, they are both rational numbers. As 0.54732814 is a rational number and 0.5 is a rational number, their product will also be a rational number.
Yes.2 and 0.5 are both rational. But 2^0.5, which is sqrt(2), is irrational.
There are no consecutive rational numbers. Between any two rational numbers there are an infinity of rational numbers.
Find the arithmetic average of the two rational numbers. It will be a rational number and will be between the two numbers.
The way in which the binary functions, addition and multiplication, are defined on the set of rational numbers ensures that the set is closed under these two operations.
11*27 = 297
Uhh... okay then... 500 and 2.
-1, -3