parallel
The lines are mutually perpendicular.
At the point (2, 4).
2X + 5Y = 6 5Y = - 2X + 6 Y = - 2/5X + 6/5 ----------------------------------and 5X - 2Y = 8 2Y = - 5X + 8 Y = - 5/2 + 4 ------------------- Look like intersecting lines, though not perpendicular
i am guessing here that this is what you mean as it involves substitution: 2x-2y = 4 therefore -2y = 4 - 2x Sub the above line into the first equation gives: 13x - 2x +4 = 70 11x = 66 x=6 then sub in x 13(6) - 2y = 70 78 - 2y = 70 y=4 Yep, this is the exact same as simultaneous equations
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines
parallel
They are straight lines.
If you mean: y = 2x and 2y = -x+4 then they are positive and negative straight line equations
The lines are mutually perpendicular.
-2X + 2Y = 4 2Y = 2X + 4 Y = X +2 by inspection, 2 but, you could also 0 out X in original equation -2(0) + 2Y = 4 2Y = 4 Y = 2
At the point (2, 4).
2X + 5Y = 6 5Y = - 2X + 6 Y = - 2/5X + 6/5 ----------------------------------and 5X - 2Y = 8 2Y = - 5X + 8 Y = - 5/2 + 4 ------------------- Look like intersecting lines, though not perpendicular
-2x + 2y = 4 is equivalent to twice -2 + y = 2 which is the equation of a straight line.
Put in function form. - 2X + 2Y = 4 2Y = 2X + 4 Y = X + 2 -------------set to 0 X + 2 = 0 X = -2 --------------X intercept
4x + 2y = -8 → 2y = -4x - 8 → y = -2x - 4
Solve for y: 2x+2y=8 2y=-2x+8 y=-x+4 f(x)=-x+4 I think that's what you mean.