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The equations (2x) and (2y - x = 4) represent two lines in a Cartesian coordinate system. The equation (2x) is simply a vertical line at (x = 0), while the equation (2y - x = 4) can be rearranged to slope-intercept form as (y = \frac{1}{2}x + 2), indicating a line with a positive slope. Therefore, the first line is vertical, and the second line is slanted with a positive slope.
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What type of lines are these y equals 2x plus 4 and 2y equals -4 plus 10?
parallel
What type of lines are these y2x 4 and 2y-4x 10?
To determine the type of lines represented by the equations ( y = 2x + 4 ) and ( y = 2x + 5 ), we can observe their slopes. Both equations have the same slope of 2, indicating that they are parallel lines. Since parallel lines never intersect, they will never meet at any point on the graph.
What kind of lines are y equals 2X plus 4 and X plus 2Y equals twelve?
The lines are mutually perpendicular.
What lines would these be 2x plus 5y equals 6 and 5x-2y equals 8?
2X + 5Y = 6 5Y = - 2X + 6 Y = - 2/5X + 6/5 ----------------------------------and 5X - 2Y = 8 2Y = - 5X + 8 Y = - 5/2 + 4 ------------------- Look like intersecting lines, though not perpendicular
Where do lines 6x-2y equals 4 and 2x plus y equals 8 intersect?
At the point (2, 4).
What type of lines are these y equals 2x plus 4 and 12 equals 2y plus x?
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines
What type of lines are these y equals 2x plus 4 and 2y equals -4 plus 10?
parallel
What type of lines are these y equals 2x plus 4 and x plus 2y equals 12?
They are straight lines.
Which type of lines are these y2x and 2y-x plus 4?
If you mean: y = 2x and 2y = -x+4 then they are positive and negative straight line equations
What type of lines are these y2x 4 and 2y-4x 10?
To determine the type of lines represented by the equations ( y = 2x + 4 ) and ( y = 2x + 5 ), we can observe their slopes. Both equations have the same slope of 2, indicating that they are parallel lines. Since parallel lines never intersect, they will never meet at any point on the graph.
What kind of lines are y equals 2X plus 4 and X plus 2Y equals twelve?
The lines are mutually perpendicular.
How do you find y intercept for -2x plus 2y equals 4?
-2X + 2Y = 4 2Y = 2X + 4 Y = X +2 by inspection, 2 but, you could also 0 out X in original equation -2(0) + 2Y = 4 2Y = 4 Y = 2
Where do lines 6x-2y equals 4 and 2x plus y equals 8 intersect?
At the point (2, 4).
What lines would these be 2x plus 5y equals 6 and 5x-2y equals 8?
2X + 5Y = 6 5Y = - 2X + 6 Y = - 2/5X + 6/5 ----------------------------------and 5X - 2Y = 8 2Y = - 5X + 8 Y = - 5/2 + 4 ------------------- Look like intersecting lines, though not perpendicular
What is -2x plus 2y equals 4?
-2x + 2y = 4 is equivalent to twice -2 + y = 2 which is the equation of a straight line.
What is the x intercept for -2x plus 2y equals 4?
Put in function form. - 2X + 2Y = 4 2Y = 2X + 4 Y = X + 2 -------------set to 0 X + 2 = 0 X = -2 --------------X intercept
What is 4x plus 2y equals -8 written in slope-intercept form?
4x + 2y = -8 → 2y = -4x - 8 → y = -2x - 4
