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Q: Which type of lines are these y2x and 2y-x plus 4?

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No because it's not a simultaneous equation but some kind of algebraic expression

2x + 2y = 14 eqn 12x - y = 5 eqn 2Solve for X and Y.Simplify eqn 2 to solve for y2x - y = 5subtract sx from both sides-y = 5 - 2xmultiple both sides by -1y = 2x - 5substitute 2x - 5 into eqn 1 for y2x + 2y = 142x + 2(2x -5) = 142x + 4x - 10 = 146x - 10 = 14add 10 to both sides6x = 24divide both sides by 10x= 4Substitute x = 4 into eqn 2y = 2(4) - 5y = 8 - 5y = 3X = 4 and y = 3

If y is equal to 2x, the graph would be a straight line going through the origin. The line would go up and to the right, and the angle at the origin has a tangent equal to 2. This angle is between 63 and 64 degrees.

Related questions

If you mean y = 2x and y = 2x-1 then they are parallel lines because they have the same slope.

Thanks to the browser, it is not possible to tell what the inequalities are.

It is an expression in two variables, x and y.

6

If you mean: y = 2x+8 then it is a straight line equation whereas 2 is the slope and 8 is the y intercept

If you mean: y = 2x+5 then it is a straight line equation.

If you mean: y = 6x+11 and y = 2x+7 Then by substitution: x = -1 and y = 5

The y value will equal 15, when x = 7

Since there is no equality (or inequality) sign in the question, there is no equation or inequality) and therefore nothing which can be solved.

x=8 y=x-5 y=

y2x - just double the coordinate of y to get x. xy12 - i have no idea

Without any equality signs the given expression can't be considered to be straight line equations.

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