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What are the x-solutions for the equation below 10x2 - 56 equals 88 - 6x2?

10x2 - 56 = 88 - 6x2 : 10x2 + 6x2 = 88 + 56 : 16x2 = 144 : x2 = 9 : x = ± 3


What are the x solutions for the equation 10x2 - 64 equals 36 plus 6x2?

10x2 - 64 = 36 + 6x2; whence, 4x2 - 100 = 0, x2 = 25, and x = ±5.


Which values of x are soluteto the equation below 15x2-56 equal 88 plus 6x2?

If: 15x2-56 = 88+6x2 Then: 9x2 = 144 And: x2 = 16 So: x = 4


What are the x-solutions for the equation 10x2-64 equals 36 plus 6x2?

If: 10x2-64 = 36+6x2 Then: 4x2-100 = 0 And: (2x-10)(2x+10) = 0 So: x = 5 or x = -5


6x2 - x - 5?

This is the equation of a parabola.


What are the x-solutions for the equation below 15x2 - 56 equals 88 plus 6x2?

15x2-56 = 88+6x2 15x2-6x2-56-88 = 0 9x2-144 = 0 Divide all terms by 9:- x2-16 = 0 (x-4)(x+4) = 0 x = 4 or x = -4


How many solutions does 6x2-7x-40 equals 0 have?

It has two solutions and they are: x = 3.230396696 and x = -2.063730029


What are the x solutions for the equation 10x2 64 equals 36 plus 6x2?

If the 64 has a minus sign, then the solution is x = +/-5 Simplifying gives 4x squared = 100 ie x squared = 25...


How do you factor the equation -x3 6x2-9x?

-x(x - 3)(x - 3)


What is the meaning of solution in math?

In an equation an answer that can be substituted for a variable that makes the equation true. Wich is a answer for any tipe of proumblem (ex. 6x2=12)


What are the roots of the quadratic equation 6x2-x15 equals 0?

In the absence of a proper statement of the equation I can only guess at answers. How about (2x + 3)(3x - 5) which is the factorisation of 6x2 - x - 15 = 0? In which case x = -2/3 or 5/3.


The quadratic term in 6x2 - 4x plus 25 is 6x2?

the equation 6x^2 - 4x + 25 is a quadratic equation due to the 6x^2 term. Whatever number on the x squared term changes it to a quadratic equation if you were to get rid of the 6x^2 then the equation would simply be -4x+25 making it simply a linear equation. when ever you have an x raised to 2 that term is the quadratic term in the equation.