10x2 - 64 = 36 + 6x2; whence,
4x2 - 100 = 0,
x2 = 25, and
x = ±5.
There are no real solutions because the discriminant of the quadratic equation is less than zero.
It is a quadratic equation and its solutions can be found by using the quadratic equation formula.
10x2 - 64 = 36 + 6x2 Combine like terms: 4x2 = 100 Divide both sides by 4: x2 = 25 Take square roots: x = -5 or +5
is an equation of a line in plane coordinate geometry. The coordinates of every point on that line satisfy the equation so there are an infinite number of solutions to the equation.
Strictly speaking the above equation is a tautological equation or an IDENTITY. An identity is true for all values of any variables that appear in it. Thus, the above "equation" is true for all value of x. - that is, it has infinitely many solutions.
If: 10x2-64 = 36+6x2 Then: 4x2-100 = 0 And: (2x-10)(2x+10) = 0 So: x = 5 or x = -5
If the 64 has a minus sign, then the solution is x = +/-5 Simplifying gives 4x squared = 100 ie x squared = 25...
There are 120 solutions.
There are no real solutions because the discriminant of the quadratic equation is less than zero.
It is a quadratic equation and its solutions can be found by using the quadratic equation formula.
No. It's a quadratic equation, and it has two solutions.
10x2 - 64 = 36 + 6x2 Combine like terms: 4x2 = 100 Divide both sides by 4: x2 = 25 Take square roots: x = -5 or +5
1
2 this Domo
no
One.
zero solutions. If you plot these two lines, you will see that they are parallel and do not intersect.