5 + 5 does not equal eleven because If we were to take 5 people and add 5 more people we would have ten people.
5(r+5) is.
13
a(r) = 2pi*r^2 and d = 2r 5 = 2r => r = 5/2 a(r) = 2pi*(5/2)^2 a(r) = 2pi*25/4 a(r) = 25pi/2 or, in decimal form, 39.2699 millimetres2
(r + 5)(r + 5)
5 + 5 does not equal eleven because If we were to take 5 people and add 5 more people we would have ten people.
There are 10 different groups of 3 people that can be formed from a group of 5 people. This can be calculated using the combination formula, which is nCr = n! / r!(n-r)!, where n is the total number of people and r is the number of people in each group.
5(r+5) is.
inaustralia you r aloud over 5 snappers
13
r2 + r - 20 = 0(r + 5)(r - 4) = 0r + 5 = 0 or r - 4 = 0r = -5 or r = 4
6
Moment of inertia of hollowsphere = 2/5 M(R^5-r^5)/(R^3-r^3)
No, they are not.
if: r = 5z 15z = 3y then: z = y/5 r = 5(y/5) r = y
factor out the common monomial, 5. 5(r^3-1) Factor as a difference of cubes. 5(r-1)(r^2+r+1)
5*[sqrt(r)]5 = 27 => r = 1.9632, approx.