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Let y=ce^(rx). R^2+r+1=0. Quadratic equation to find R.
-9
It's an incorrect statement. 5 plus 6 equals plus 11. Also, pi R round, cornbread R2 .
10+r = 2r Subtract r from both sides:- r = 10
Solving for r: 16r2+18r+5=0 (2r+1)(8r+5)=0 2r+1=0 and 8r+5=0 2r=-1 .......... 8r=-5 r= -1/2 ........ r= -5/8
(2-r)e-rr
r + s = 4 and 2r + 3s = 8 multiply the first equation by 2 giving 2r + 2s = 8 subtract this from the second equation giving s = 0 So r = 4 and s = 0.
3+10-r+6r = -3+9r+0 13+5r = -3+9r 16 = 4r r = 4
This is the associative law for addition: If a, b, c are any numbers then: a + (b + c) = (a + b) + c
r=0 is the solution...
r=-29
r=2
A circle centre (0, 0) and radius r has equation x² + y² = r² The circle x² + y² = 36 has: r² = 36 → radius = 6
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r+5r+5=-25
Let y=ce^(rx). R^2+r+1=0. Quadratic equation to find R.