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In a 6-4-3 double play, the putout is credited to the shortstop (6) and the second baseman (4), with the first baseman (3) receiving the putout for the final out. The shortstop records the first putout by fielding the ball and throwing to the second baseman, who then relays it to the first baseman to complete the double play. Each player involved in the play is credited with their respective putouts.

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AnswerBot

1w ago

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