(125 ft/sec) x (1 mi / 5280 ft) x (3600 sec / 1 hr) = (125 x 3600 / 5280) (ft - mi - sec / sec - ft - hr) =85.227 mph (rounded)
Period of 0.008 sec = Frequency of (1/0.008) = 125 Hz.
First change mi/hr into ft/sec. There 1 mi = 5280 ft and 1 hour = 3600 sec. 6 mi/hr = 6 * (5280 ft / 3600 sec) = 8.8 ft / sec To figure out how fast you travel any distance you divide the distance by time it took you. distance / time = speed 205 ft / time = 8.8 ft / sec Solving for time: time = 205 ft / (8.8 ft / sec) time = 23 sec
sec
speed = distance / time 100 m / 25 sec = 4 m/sec
(125 ft/sec) x (1 mi / 5280 ft) x (3600 sec / 1 hr) = (125 x 3600 / 5280) (ft - mi - sec / sec - ft - hr) =85.227 mph (rounded)
The Sampling time means that at how much interval of time the continuous time signal is recorded For example If we have a simple square wave starting from 0 sec and ends at 5 sec with magnitude of 1 and let sampling time is Ts=0.5 second Then the no. of samples obtained will be after each 0.5 second. So total number of samples will be 10. Check it graphically and it will be more easy to understand. By Armaghan Zafar
SEC is on ESPNU wich is on channel 125 or 725 if you watch it in HD
PCM technique is used to convert analog voice signals into digital. In PCM the analog frequency is first sampled and then converted into binary bits. Each samples are taken as 8bits long. Basic communication theory requires that a minimum sampling rate of twice the frequency of the signal to be sampled will result in an accurate representation of the original signal.Human voice can have max 4000hz frequency, therefore sampling rate should be 8000 samples/sec.Which implies required bit rate for transmitting voice is 8000*8 = 64000 bits/sec = 64kbps.
Every city is different, so check with your local listing.
Acceleration = (change in speed) / (change in time) = [ (54 - 36) km/hr ] / (10 sec) = (18 km/hr) /(10 sec) = (1.8 km/hr-sec) x (3,600 sec / hr) = (1.8 x 3,600) (km - sec / hr2 - sec) = 6,480 km / hr2 Average speed during the 10 seconds = (36 + 54) / 2 = 90/2 = 45 km/hr Distance = (average speed) x (time) = (45 km/hr) x (10 sec) x (1 hr / 3,600 sec) = (45 x 10 / 3,600) (km - sec - hr / hr - sec) = 0.125 km = 125 meters
main() { int sec=00,min=00,hr=00; printf("Enter time in seconds"); scanf("%d",&sec); if (sec<60) printf("%d :%d : %d",hr,min,sec); else if(sec>=60) min=int(sec/60); sec=int(sec%60); printf("%d: %d : %d",hr,min,sec); else if (sec>=3600) min=int(sec/60); sec=int(sec/60) hr=int(min/60); printf("%d : %d : %d",hr,sec,min); }
Period of 0.008 sec = Frequency of (1/0.008) = 125 Hz.
First change mi/hr into ft/sec. There 1 mi = 5280 ft and 1 hour = 3600 sec. 6 mi/hr = 6 * (5280 ft / 3600 sec) = 8.8 ft / sec To figure out how fast you travel any distance you divide the distance by time it took you. distance / time = speed 205 ft / time = 8.8 ft / sec Solving for time: time = 205 ft / (8.8 ft / sec) time = 23 sec
6.2 sec manual. 7.0 sec automatic 6.2 sec manual. 7.0 sec automatic
men 10.28 sec women 11.42 sec
sec