Actually, it is possible - if you calculate with complex numbers.
In the real numbers... Let's see an example.
Asking for x = log101000 (the base may be assumed, but I will include it here for clarity) is like asking: 10x = 1000. Clearly, the solution is 3.
Asking for x = log100.001 is the same as asking 10x = 0.001; the solution is -3.
But asking for x = log10(-1) is like asking 10x = -1. This doesn't have any solution; for positive values of "x" the right side (the result of taking the power) will be more than 1, for negative values of "x", the right side will be less than 1, but always more than zerowill. If x approaches minus infinity, the result of the power will approach zero - but it will never reach zero, nor will it be less than zero. Do some powers on your calculator to help you visualize this.
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This is not possible, because any number squared would be positive, not negative.
Of course it is. 'a' can be any positive or negative number, and 'b' is its square.That's no problem.What is difficult is for 'b' to be a negative number in the same equation.No real number for 'a' can produce a negative 'b'.
Logs are defined only for positive numbers so the log of a negative number does not exist.
4. i is just the imaginarY number used in an equatiOn, where there is a negative root (not possible to have a negative root) All yoU do is multiply the negative Root with a negative one, and you'll See your answer. absoluTe valUe turns any negative number into a Positive, even an Imaginary number. Do this and you'll be fine with your trigonometry!
if you mean like, (-10)/5, then yes, it is simply a negative fraction, which works just like negative numbers.