Yes. The logarithm of 1 is zero; the logarithm of any number less than one is negative. For example, in base 10, log(0.1) = -1, log(0.01) = -2, log(0.001) = -3, etc.
No. The range of the exponential (antilog) function is the positive reals (unless you are dealing with the complex field).
The logarithm function is the inverse of the exponential function. Take the exponential function (base 10): y = 10x. The inverse of this is x = 10y. The function y = log(x) is used to define this inverse function. First look at y = 10x. Any real value of x will yield a positive real value for y. If x = 0, then y = 1; if x < 0 (negative) then y is between 0 and 1 (it will never equal zero, though). A value of 10-99999 is very close to zero, but not quite there. There are no real values of x which will give a negative y value for y = 10x. Now look at y = log(x) or x = 10y. No matter what real values for y, that we choose, x will always be a positive number, so a negative value of x in y = log(x) is not possible if you are limiting to real numbers. It is possible with complex and imaginary numbers to take a log of a negative number, or to get a negative answer to y = 10x.
There is no answer - it is an error: negative numbers do not have logarithms. The log if a number tells to what power the (positive) base must be raised to get the number. Raising any positive number to any power will never result in a negative number, so it is an error to try and take the log of a negative number.
In order to find the log with a power of ten, use the LOG button. For example, to find log105, type log(5). (The parenthesis after the g will appear when you press the LOG button. In order to find a log with a power other than ten, you will have to divide by the log10 of that power. For example, to find log82, type log(8)/log(2). In order to find the natural log of a number, use the LN key. For example, to find the natural log of 91, type ln(91).
Yes. The logarithm of 1 is zero; the logarithm of any number less than one is negative. For example, in base 10, log(0.1) = -1, log(0.01) = -2, log(0.001) = -3, etc.
some times dams have negitives effects I added the answer below to a link of a Yahoo answer; however, it IS possible to calculate the log of a negative number but you have to work in complex numbers.
The negative log of a number is the log of the number's reciprocal ('1' divided by the number).
No. The range of the exponential (antilog) function is the positive reals (unless you are dealing with the complex field).
A logarithm of a reciprocal. For example, log(1/7) or log(7-1) = -log(7)
There really is no difference. Some people just say it differently.
You can't take the log of negative numbers - at least, not while you stay in the realm of real numbers.You can't take the log of negative numbers - at least, not while you stay in the realm of real numbers.You can't take the log of negative numbers - at least, not while you stay in the realm of real numbers.You can't take the log of negative numbers - at least, not while you stay in the realm of real numbers.
It is not possible.
The logarithm of a number less than 1 is negative. Therefore, -log 0.5 is the negative logarithm of 0.5 which is equal to -0.301.
The logarithm function is the inverse of the exponential function. Take the exponential function (base 10): y = 10x. The inverse of this is x = 10y. The function y = log(x) is used to define this inverse function. First look at y = 10x. Any real value of x will yield a positive real value for y. If x = 0, then y = 1; if x < 0 (negative) then y is between 0 and 1 (it will never equal zero, though). A value of 10-99999 is very close to zero, but not quite there. There are no real values of x which will give a negative y value for y = 10x. Now look at y = log(x) or x = 10y. No matter what real values for y, that we choose, x will always be a positive number, so a negative value of x in y = log(x) is not possible if you are limiting to real numbers. It is possible with complex and imaginary numbers to take a log of a negative number, or to get a negative answer to y = 10x.
There is no answer - it is an error: negative numbers do not have logarithms. The log if a number tells to what power the (positive) base must be raised to get the number. Raising any positive number to any power will never result in a negative number, so it is an error to try and take the log of a negative number.
Well, darling, to find the antilog of a negative number using a log table, you first need to find the positive equivalent of the negative number. Add the negative number to the log base, and then look up the result in the log table to find the antilog value. Just remember, math doesn't have time for negativity, so keep it positive!