Logs are defined only for positive numbers so the log of a negative number does not exist.
Yes. The logarithm of 1 is zero; the logarithm of any number less than one is negative. For example, in base 10, log(0.1) = -1, log(0.01) = -2, log(0.001) = -3, etc.
No. The range of the exponential (antilog) function is the positive reals (unless you are dealing with the complex field).
The logarithm function is the inverse of the exponential function. Take the exponential function (base 10): y = 10x. The inverse of this is x = 10y. The function y = log(x) is used to define this inverse function. First look at y = 10x. Any real value of x will yield a positive real value for y. If x = 0, then y = 1; if x < 0 (negative) then y is between 0 and 1 (it will never equal zero, though). A value of 10-99999 is very close to zero, but not quite there. There are no real values of x which will give a negative y value for y = 10x. Now look at y = log(x) or x = 10y. No matter what real values for y, that we choose, x will always be a positive number, so a negative value of x in y = log(x) is not possible if you are limiting to real numbers. It is possible with complex and imaginary numbers to take a log of a negative number, or to get a negative answer to y = 10x.
In order to find the log with a power of ten, use the LOG button. For example, to find log105, type log(5). (The parenthesis after the g will appear when you press the LOG button. In order to find a log with a power other than ten, you will have to divide by the log10 of that power. For example, to find log82, type log(8)/log(2). In order to find the natural log of a number, use the LN key. For example, to find the natural log of 91, type ln(91).
It is because the logarithm function is strictly monotonic.
Yes. The logarithm of 1 is zero; the logarithm of any number less than one is negative. For example, in base 10, log(0.1) = -1, log(0.01) = -2, log(0.001) = -3, etc.
some times dams have negitives effects I added the answer below to a link of a Yahoo answer; however, it IS possible to calculate the log of a negative number but you have to work in complex numbers.
The negative log of a number is the log of the number's reciprocal ('1' divided by the number).
No. The range of the exponential (antilog) function is the positive reals (unless you are dealing with the complex field).
To find the pH of two compounds given together, calculate the individual pH of each compound first using their respective concentrations and equilibrium constants. Then, consider the combined effect of both compounds on the overall pH, taking into account any interactions or reactions that may occur. If the compounds do not interact, you can find the overall pH by averaging the individual pH values based on their relative concentrations.
There really is no difference. Some people just say it differently.
A logarithm of a reciprocal. For example, log(1/7) or log(7-1) = -log(7)
You can't take the log of negative numbers - at least, not while you stay in the realm of real numbers.You can't take the log of negative numbers - at least, not while you stay in the realm of real numbers.You can't take the log of negative numbers - at least, not while you stay in the realm of real numbers.You can't take the log of negative numbers - at least, not while you stay in the realm of real numbers.
It is not possible.
The logarithm of a number less than 1 is negative. Therefore, -log 0.5 is the negative logarithm of 0.5 which is equal to -0.301.
The logarithm function is the inverse of the exponential function. Take the exponential function (base 10): y = 10x. The inverse of this is x = 10y. The function y = log(x) is used to define this inverse function. First look at y = 10x. Any real value of x will yield a positive real value for y. If x = 0, then y = 1; if x < 0 (negative) then y is between 0 and 1 (it will never equal zero, though). A value of 10-99999 is very close to zero, but not quite there. There are no real values of x which will give a negative y value for y = 10x. Now look at y = log(x) or x = 10y. No matter what real values for y, that we choose, x will always be a positive number, so a negative value of x in y = log(x) is not possible if you are limiting to real numbers. It is possible with complex and imaginary numbers to take a log of a negative number, or to get a negative answer to y = 10x.
1