because the oxygen needs to be diffused very easily and quickly aross the alveoli
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Leaves are broad, thin and flat to provide a large surface area, to absorb sunlight for photosynthesis. :)
It is not possible. For example, the prism could be tall and thin, or short and thick, and either way have the same surface area.
It means that someone has recorded the dimensions of a thin object with rather a large area, possibly with the aim of calculating its volume. However, it is equally possible that the dimensions are recorded to establish its surface area (for painting?).
You cannot find a unique solution because blocks of different shapes and volumes can still have the same surface area.You can find the dimensions of a cube with the given surface area; it is the largest volume of a rectangular prism for a given surface area.A cube has six equal square sides. Take the total surface area "At", divide this by 6 to get the area of one side "As":At / 6 = AsThe length Ls of one side of the cube is the square root of As .Ls = sqrt (As ) = sqrt (At / 6 )All the edges of a cube are of course the exact same length.Another solution is a very thin square prism (almost a sheet but with a finite thickness) with the top and bottom just slightly less than half the surface area; the remainder has to be spread out along the edge which can be arbitrarily narrow.Theoretically you can have a very long rectangular prism and so very large values for the length if the height and width are very small and still have the surface area set out in the problem.
The question does not specify what the required formula is for: the volume of an open cylinder, height, radius, surface area, etc. Furthermore, information on the total surface area of a cylinder will not provide sufficient information. A short wide cylinder can have the same surface area as a tall thin one. For example, radius 5 cm and height 4 cm or radius 4 cm and height 7.5 cm or radius 3 cm and height 12 cm or radius 2 cm and height 20.5 cm etc all have the same total surface area. But in each case the value of the other measure, for the open cylinder will be different.