The unit g/cm³ (grams per cubic centimeter) is used for density because it expresses mass per unit volume. Specifically, it indicates how many grams of a substance are contained in one cubic centimeter of space. This unit is convenient for measuring the density of solids and liquids, particularly in laboratory and scientific contexts, where the cubic centimeter is a manageable volume for small samples.
the mks unit is kg/m cube and the cgs unit is g/cm cube
To find the density of the cube, you can use the formula: density = mass/volume. The volume of a cube is calculated as side³, so for a side of 5 cm, the volume is 5 cm × 5 cm × 5 cm = 125 cm³. Given the mass is 250 grams, the density is 250 g / 125 cm³ = 2 g/cm³. Thus, the density of the cube is 2 g/cm³.
To determine if a solid cube with 6-cm sides and a mass of 270 g would float, we need to calculate its density and compare it to the density of water. The volume of the cube is (6 , \text{cm} \times 6 , \text{cm} \times 6 , \text{cm} = 216 , \text{cm}^3). The density of the cube is ( \frac{270 , \text{g}}{216 , \text{cm}^3} \approx 1.25 , \text{g/cm}^3), which is greater than the density of water (1 g/cm³). Therefore, the cube would not float.
To determine if the solid cube will float, we need to calculate its density and compare it to the density of water (1 g/cm³). The volume of the cube is (6 \text{ cm} \times 6 \text{ cm} \times 6 \text{ cm} = 216 \text{ cm}^3). The density of the cube is ( \frac{270 \text{ g}}{216 \text{ cm}^3} \approx 1.25 \text{ g/cm}^3). Since the density of the cube is greater than that of water, it will not float and will sink instead.
We know that density=mass/volume so the density of the cube= 16 g (the mass)/64 cubic cm= 0.25 g/cubic cm
the mks unit is kg/m cube and the cgs unit is g/cm cube
To find the density of the cube, you can use the formula: density = mass/volume. The volume of a cube is calculated as side³, so for a side of 5 cm, the volume is 5 cm × 5 cm × 5 cm = 125 cm³. Given the mass is 250 grams, the density is 250 g / 125 cm³ = 2 g/cm³. Thus, the density of the cube is 2 g/cm³.
The volume of the cube is (5.0 cm)^3 = 125 cm^3. To find the density, divide the mass by the volume: density = mass / volume = 250 g / 125 cm^3 = 2 g/cm^3. The density of the cube is 2 g/cm^3.
Volume of cube = 6^3 = 216 cm^3 Density of cube = 270 g / 216 cm^3 = 1.25 g cm^-3 This cube would not float in water as its density is greater than the density of water at 1 g cm^3
The volume of the gold cube is calculated as side cubed (4 cm * 4 cm * 4 cm) = 64 cm^3. Density is mass divided by volume (1235 g / 64 cm^3 ≈ 19.3 g/cm^3). So, the density of the gold cube is approximately 19.3 g/cm^3.
The density of the cube is calculated by dividing the mass of the cube by the volume of the cube. The volume of a cube is given by the formula side length cubed, so the density of the cube would be mass (g) divided by side length (cm) cubed.
To determine if the solid cube will float, we need to calculate its density and compare it to the density of water (1 g/cm³). The volume of the cube is (6 \text{ cm} \times 6 \text{ cm} \times 6 \text{ cm} = 216 \text{ cm}^3). The density of the cube is ( \frac{270 \text{ g}}{216 \text{ cm}^3} \approx 1.25 \text{ g/cm}^3). Since the density of the cube is greater than that of water, it will not float and will sink instead.
The volume of the cube is calculated by V = side length^3 = (1.5 cm)^3 = 3.375 cm^3. The density is then calculated by dividing mass by volume: Density = mass/volume = 1.0 g / 3.375 cm^3 = 0.296 g/cm^3.
The volume of the cube is (3 \times 3 \times 3 = 27 , \text{cm}^3). Density is calculated by dividing mass by volume, so the density of the cube would be (27 , \text{g} \div 27 , \text{cm}^3 = 1 , \text{g/cm}^3).
We know that density=mass/volume so the density of the cube= 16 g (the mass)/64 cubic cm= 0.25 g/cubic cm
The density of water is 1 g/cm³. So, the volume of the cube of water would be equal to its mass divided by its density, which is 512g / 1 g/cm³ = 512 cm³.
This substance has density of 18 g/cm3