It may be because you do not understand the process yourself!
This is not possible, because any number squared would be positive, not negative.
No. All whole numbers are integers.
Logs are defined only for positive numbers so the log of a negative number does not exist.
Of course it is. 'a' can be any positive or negative number, and 'b' is its square.That's no problem.What is difficult is for 'b' to be a negative number in the same equation.No real number for 'a' can produce a negative 'b'.
It is rational because it can be expressed as the ratio 400040004/10000000000.
Let x and y be two rational numbers. If both x and y are negative then their sum will be negative.If only one of them, say x, is positive (so that y is negative), and if the absolute value (or magnitude) of y is greater than x then their sum will be negative.
Of course it is! If the mean of a set of data is negative, then the coefficient of variation will be negative.
This is not possible, because any number squared would be positive, not negative.
No. All whole numbers are integers.
Logs are defined only for positive numbers so the log of a negative number does not exist.
Of course it is. 'a' can be any positive or negative number, and 'b' is its square.That's no problem.What is difficult is for 'b' to be a negative number in the same equation.No real number for 'a' can produce a negative 'b'.
Yes, it is possible to do negative work in a physical system. Negative work occurs when the force applied to an object is in the opposite direction of its displacement. This results in the object losing energy rather than gaining it.
It is rational because it can be expressed as the ratio 400040004/10000000000.
No, 1/2 is rational, but not a whole number.
It must be a generalised rational number. Otherwise, if you select a rational number to multiply, then you will only prove it for that number.
It can be written in the form of the ratio 55555/100000.
A rational number is, by definition, the answer from dividing one integer by another.