A polygon is a plane shape in which an area is enclosed by straight lines that meet pairwise.
Two lines cannot enclose an area. Either they are parallel and there are two gaps to the area between them or they meet at an angle and there is a gap in the enclosure opposite the angle.
So there must be at least three sides. Now three lines, taken two at a time create three distinct vertices (a triangle). So the least number of vertices is 3.
square
If it is a polygon with an even number (>2) of vertices, join any two pairs of opposite vertices. These lines will meet in the centre. If it is a polygon with an odd number (>1) of vertices, join any two vertices to the midpoints of the opposite sides. These lines will meet in the centre.
Depending on which two vertices, it could be a side and it could be a diagonal.
The number of sides and vertices in any polygon is always the same.
The answer is 324 degrees. The general formula is (n-2)*180 degrees, where n=number of sides/vertices(both are same). But this is valid only for convex polygon (every internal angle is strictly less than 180 degrees & every line segment between two nonadjacent vertices of the polygon is strictly interior to the polygon except at its endpoints)
no
No vertices (0). a heart shape is not a polygon shape, only polygon shapes have vertices.
square
square
If it is a polygon with an even number (>2) of vertices, join any two pairs of opposite vertices. These lines will meet in the centre. If it is a polygon with an odd number (>1) of vertices, join any two vertices to the midpoints of the opposite sides. These lines will meet in the centre.
A polygon has the same number of vertices as it has sides. So a pentagon has 5 and an octagon has 8, etc.
Depending on which two vertices, it could be a side and it could be a diagonal.
The formula to calculate the number of diagonals in a polygon is n(n-3)/2, where n represents the number of vertices. Setting this formula equal to 560 and solving for n, we get n(n-3)/2 = 560. By solving this quadratic equation, we find that the polygon has 20 vertices.
The number of sides and vertices in any polygon is always the same.
A diagonal.
Infinitely many. For each integer n (greater than 2), there is a polygon with n sides or n vertices.
The answer is 324 degrees. The general formula is (n-2)*180 degrees, where n=number of sides/vertices(both are same). But this is valid only for convex polygon (every internal angle is strictly less than 180 degrees & every line segment between two nonadjacent vertices of the polygon is strictly interior to the polygon except at its endpoints)