The formula to calculate the number of diagonals in a polygon is n(n-3)/2, where n represents the number of vertices. Setting this formula equal to 560 and solving for n, we get n(n-3)/2 = 560. By solving this quadratic equation, we find that the polygon has 20 vertices.
A diamond shape has two diagonals. A diagonal is a line segment that connects two non-adjacent vertices in a polygon. In a diamond shape, there are four vertices, and two of these vertices are non-adjacent to each other. Therefore, a diamond has two diagonals.
A 3-sided polygon is a triangle. There is no diagonal for that shape since all non-adjacent vertices share a line segment!
In a hexagon, each vertex can connect to all other non-adjacent vertices to form diagonals. Since a hexagon has 6 vertices, each vertex can form diagonals with the other 4 non-adjacent vertices. Therefore, each vertex of a hexagon can create 4 diagonals. This results in a total of 6 vertices x 4 diagonals = 24 diagonals in a hexagon.
19. sides=vertices
A polygon has as many vertices as it has sides and so in this case it will have 20 vertices.
n-3 diagonals. Of the n vertices of the polygon, you cannot draw diagonals to the two adjacent vertices since these are sides of the polygon and so not diagonals. And you cannot draw a diagonal from a vertex to itself. So those are three vertices that are ruled out, leaving n-3.
A polygon with n vertices has n*(n-3)/2 diagonals. So an octagon has 8*5/2 = 20 diagonals. Of those 20 diagonals, 8 are the principal diagonals, the ones joining a pair of opposite vertices
Using the formula 0.5(n^2 -3n) whereas n is number of sides, altogether there are 104 diagonals in a 16 sided polygon
A diamond shape has two diagonals. A diagonal is a line segment that connects two non-adjacent vertices in a polygon. In a diamond shape, there are four vertices, and two of these vertices are non-adjacent to each other. Therefore, a diamond has two diagonals.
10 ... any polygon it is 2 less than the number of sides or vertices wince they are the same.
A 3-sided polygon is a triangle. There is no diagonal for that shape since all non-adjacent vertices share a line segment!
47 sides. Take a vertex of an n-sided polygon. There are n-1 other vertices. It is already joined to its 2 neighbours, leaving n-3 other vertices not connected to it. Thus n-3 diagonals can be drawn in from each vertex. For n=50, n-3 = 50-3 = 47 diagonals can be drawn from each vertex. The total number of diagonals in an n-sided polygon would imply n-3 diagonals from each of the n vertices giving n(n-3). However, the diagonal from vertex A to C would be counted twice, once for vertex A and again for vertex C, thus there are half this number of diagonals, namely: number of diagonals in an n-sided polygon = n(n-3)/2.
That polygon is called a "triangle". It has no diagonals.
how many diagonals are there iin a polygon of 11 sides
An 11 sided polygon has 44 diagonals.
There are 90 diagonals in a 15-sided polygon.
A four-sided polygon has two diagonals.