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Sure you can substitute that. You just have to be careful to avoid division by zero - but the same may happen with other numbers as well. For example:

- If you have a denominator "x", then you can't substitute "x" by zero.
- If you have a denominator "x - 1", then you can't substitute "x" by 1, because if you do, the denominator will be zero.

Q: Why can't you substitute 0 for a variable in an expression?

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-8 + 13/N, where N â‰ 0.

1/x + 2, provided x is not 0. If x is 0, the expression is undefined.

Yes they can, for example quadratic expressions are often written in the form, ax^2+bx+c, where x is a variable, and a,b,c are constants. If you have an expression such as 5x^2 - 3, then clearly a=5, c=-3 and b=0

undefined means you can not do the operation (5/0 is undefined) no solution refers to an equation not having an answer. a solution is a number which you can plug into the variable of an equation and get a true statement. So having no solution means there is no number which you can plug in and get a true statement. As a fraction is not an equation, but an expression it is not right to say that 5/0 has no solution. There is no variable in 5/0, nothing to plug into to get a true or false statement.

Related questions

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Substitute the variable in the denominator for a value that will make the denominator have a value of 0 or an imaginary number

A quadratic expression is an expression which is written in the form ax2+bx+c, where a, b, and c represent constants, x represents a variable, and a is not equal to 0.

a^(-n) = (1/a)^nIf a is 0, the above expression would require division by 0, which is not defined.

-8 + 13/N, where N â‰ 0.

An expression can be that, but it can also be a combination of such terms and other mathematical operations. For example, 3a + 27b^2/sin(27c) provided c is not 0.

1/x + 2, provided x is not 0. If x is 0, the expression is undefined.

Numerical expressions solely include numbers, while algebraic expressions may contain a variable like x. An example of a numerical expression is 1+2 and an example of an algebraic expression is 2x+3y=0.

To find the value of ( 3p^2 - 8p + 4 ), you simply substitute the value of ( p ) into the expression. If ( p ) is a specific number or variable, plug it into the equation. For example, if ( p = 2 ): [ 3p^2 - 8p + 4 = 3(2)^2 - 8(2) + 4 ] [ = 3 \cdot 4 - 16 + 4 ] [ = 12 - 16 + 4 ] [ = 0 ] Therefore, when ( p = 2 ), ( 3p^2 - 8p + 4 = 0 ). If ( p ) is a variable and not a specific number, the expression ( 3p^2 - 8p + 4 ) represents a quadratic polynomial that can be factored or evaluated depending on the context or requirements of the problem.

Z is a variable with mean 0 and variance 1.Z is a variable with mean 0 and variance 1.Z is a variable with mean 0 and variance 1.Z is a variable with mean 0 and variance 1.

So that you have an equation = to 0 and can manipulate it in one variable. Y = 2 X - 4 2X - 4 = 0 2X = 4 X = 2 check the graph and see that this is true. Works for all such functions.

For any polynomial equation, there must be no constant term.For equations in general there is no easy way. Substitute 0 for each of the variables and if the resulting expression is 0 then the line passes through the origin.