Only three significant figures.
In 25.5 the significant figures are 2,5 and 5 while in 10.09 only 1 and 9 are significant figures.
Two. When multiplying or dividing the answer is rounded to the fewest significant figures in the given measurements. 0.55 has only two significant figures, so the answer can have only two significant figures.
A number with only 1 significant figure can't be rounded to 3 significant figures
e A number that has only 1 significant figure can't be rounded to 3 significant figures
There are 10 significant figures in 8630000.000.
0.0730 has three significant figures.
There are 4 significant figures in 0.0032. Seems to be only 2 significant figures in this number.
145.992 using only four significant figures is 146.0
Only three significant figures.
In 25.5 the significant figures are 2,5 and 5 while in 10.09 only 1 and 9 are significant figures.
The accuracy of the answer is limited to the LEAST significant figures of the input. So if two measured quantities are multiplied or divided, one of which is accurate to only two significant figures, and other to six significant figures, the answer is only accurate to two significant figures. HOWEVER: use all the figures you have for the calculation, and then round your answer to two significant figures. Also, however, remember that if you are multiplying by an actual exact number, as in doubling, the significant figures of that 2 is unlimited, so the answer is only limited by the significant figures of the number you are doubling.
Two. When multiplying or dividing the answer is rounded to the fewest significant figures in the given measurements. 0.55 has only two significant figures, so the answer can have only two significant figures.
21,600 using only four significant figures is still 21,600.
There are four significant figures in 0.0001 mol.
0,000 000 32 has only two significant figures (3 and 2).
There are two significant figures in 0.020. The leading zeros are not considered significant, so only the 2 and 0 count as significant figures.