Wiki User
∙ 13y agoTo obtain a much better, simpler, and more practical understanding of the data distribution.
Wiki User
∙ 13y agoIn the same way that you calculate mean and median that are greater than the standard deviation!
msd 0.560
characteristics of mean
mean | 32 median | 32 standard deviation | 4.472 ========================================================================
mean
In the same way that you calculate mean and median that are greater than the standard deviation!
msd 0.560
characteristics of mean
The mean, median, and mode of a normal distribution are equal; in this case, 22. The standard deviation has no bearing on this question.
Mean: 26.33 Median: 29.5 Mode: 10, 35 Standard Deviation: 14.1515 Standard Error: 5.7773
mean | 32 median | 32 standard deviation | 4.472 ========================================================================
The mean deviation from the median is equal to the mean minus the median.
The median is least affected by an extreme outlier. Mean and standard deviation ARE affected by extreme outliers.
mean
mean | 30 median | 18 standard deviation | 35.496
You don't need to. The mean deviation is, by definition, zero.
To find the standard deviation, you must first compute the mean for the data set. So the answer is yes. Just have a look at the 5 steps needed to compute a standard deviation and you will see why the answer is yes. In reality, people most often use calculators or computers to do this. However, it is good to understand what they are doing. 1. Compute the deviation by subtracting the mean from each value. 2. Square each individual deviation. 3. Add up the squared deviations. 4. Divide by one less than the sample size. 5. Take the square root