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the objective lens has the power of that lens inscribed on it
Specifically if you increase the diameter of the main lens, or of the main mirror (depending on the type of the telescope), you'll be able to observe dimmer objects (stars, planets, etc.). Also, the telescope's resolving power (angular resolution) improves with a bigger mirror/lens. For example, with a bigger mirror/lens you'll be able to distinguish two stars that are closer together as separate objects.
20 refers to the amplification, 70 mm to the diameter of the main lens or mirror. Note: This diameter is by far the most important piece of information.
The eyepiece is usually 10x, so multiply the objective by 10 to get true magnification
it would be 15 times 40 which is 600 times magnification
Because the 2cm lens has 4 times the area of a 1cm lens. (area = Pi*r2)
Field diameter is calculated by measuring the distance across the field of view of a microscope, then dividing that measurement by the magnification of the objective lens being used. This gives you the field diameter in micrometers.
You can estimate the size of the object by comparing the field diameters observed under the low power objective lens (4x) and high power objective lens (40x). Calculate the ratio of the field diameters (40x/4x = 10), and use this ratio to estimate the size of the object viewed under the high power objective lens. Simply multiply the size of the object viewed under the low power objective lens by the ratio (field diameter at 4x) to get an estimation.
This is a variable power scope- from 6 power to 24 power. The front lens (objective lens) is 40mm in diameter.
It magnifies 4 times, and the objective (front lens) is 40 mm in diameter. A 3x9-40 would be a 3 to 9 power variable magnification scope, with a 40mm objective lens.
To calculate the field diameter of a medium power lens, you need to first determine the field number of the lens. The field number is typically provided by the manufacturer and represents the diameter of the field of view in millimeters. To calculate the field diameter, you divide the field number by the magnification of the lens. Field diameter = Field number / Magnification.
Yes, both have to do with the diameter of the objective mirror/lens
Typically, the low power lens magnifies a specimen by 10x. So, if you view a cell through the low power lens, the cell would be magnified 10 times its actual size.
A microscope lens with a power of 20X will magnify an object 20 times its actual size.
No, the diameter of a telescope's objective lens or mirror determines its light-gathering ability and resolving power, while the magnification is determined by the ratio of the focal length of the objective lens or mirror to the eyepiece.
The light-gathering power of a telescope is directly proportional to the area of the lens or mirror, which is determined by the square of its diameter. A larger diameter means more light can be collected, resulting in brighter and clearer images. This is why larger telescopes with bigger lenses or mirrors are favored for stargazing and deep-space observation.
A fast lens will take a parallel beam of light and focus it in a relatively short distance. For example a 1 centimetre diameter lens that focusses the light to a spot 2 centimeters after the lens is quite fast. It has a short focal length, only two times longer than the diameter of the lens. We say it is an f/2 lens. Very few fast lenses are faster than f/1. It is dificult to design fast lenses that have good image blurring, high light transmission and low image distortion. Good ones are expensive. A long focal length lens for example that focusses a parallel beam to a spot at a distance 20 times its diameter after the lens would becalled a slow lens.