Chat with our AI personalities
minimum is '0' and maximum cannot be defined
The maximum area is obtained when the fencing enclosing a circular area. Beyond that I cannot help since I do not fully understand your question.
Not quite. The point at infinity cannot be regarded as a maximum since the value will continue to increase asymptotically. As a result no polynomial of odd degree can have a maximum. Only polynomials of an even degree whose leading coefficient is negative will have a global maximum.
The area of a rhombus cannot be determined form its side lengths. The shape can be flexed into a square (when it has maximum area) to a long thin rhombus (when it has minimum area).The area of a rhombus cannot be determined form its side lengths. The shape can be flexed into a square (when it has maximum area) to a long thin rhombus (when it has minimum area).The area of a rhombus cannot be determined form its side lengths. The shape can be flexed into a square (when it has maximum area) to a long thin rhombus (when it has minimum area).The area of a rhombus cannot be determined form its side lengths. The shape can be flexed into a square (when it has maximum area) to a long thin rhombus (when it has minimum area).
Thanks to the limitation of the browser, this question is missing a symbol before the 15. If it is anything but an equality or inequality symbol, the answer is that the question concerns an expression which is neither a maximum nor a minimum. If the missing symbol is an equality equation is an infinitely long straight line. That cannot have a minimum nor a maximum. If the missing symbol is an inequality sign, the equation is a region of the plane defined by a straight line. And, as above, it cannot have a minimum nor a maximum.