Because when you divide 453 by 3, you get a whole number (a number that doesn't have a decimal or fraction) which comes out to be 151. However, when you divide 453 by 2, you get 226.5 or 226 1/2. Since this is not a whole number it is not divisible by 2. Anything divisible by 2 will end with and even number(2, 4, 6, 8, or 0(this does exclude 0 itself)) Divisibility does have rules to help
If the number is divisible by:
2 - it will end with an even number
3 - the sum of the digits will be a multiple of 3
4 - the last 2 digits will be a multiple of 4
5 - the number will end with a 5 or 0(excluding 0 again)
6 - the number is divisible by 2 and 3
7 - I haven't found any trick for 7 =( sorry
8 - the last 3 digits are divisible by 8
9 - the sum of the digits are a multiple of 9
10 - the number ends with 0(excluding 0)
Of course you could divide all of these on a calculator but here are some tricks to help.
Hope this helped =)
To get a number like this, it CANNOT be even. The number 453 is divisible by 3(goes into 453 ninenty one times), but not by 2.
By any of its factors which are: 1, 3, 151 and 453
It is divisible by 6
102 is divisible by: 1 2 3 6 17 34 51 102.
For starters, the number 3 is divisible by 3 but not by 2. Next, 9, 27 etc. All the odd multiples of 3 are divisible by 3 but not 2. So there is an infinite number of numbers that are divisible by 3 and not 2.
To get a number like this, it CANNOT be even. The number 453 is divisible by 3(goes into 453 ninenty one times), but not by 2.
453
By any of its factors which are: 1, 3, 151 and 453
Yes. The result is 151
Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.
It is divisible by 6
Any number that is divisible by both 2 and 3 is divisible by 6.
Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 2 + 3 + 4 = 9 which is divisible by 3, so 234 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 234 is even so 234 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 234 is divisible by both 2 & 3 so 234 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 2 + 3 + 4 = 9 which is divisible by 9, so 234 is divisible by 9Thus 234 is divisible by all 3, 6 & 9.
To determine if a number is divisible by 6, it must be divisible by both 2 and 3. To determine if a number is divisible by 2, it should be even - in other words, it should end with 0, 2, 4, 6, or 8. To determine if a number is divisible by 3, the sum of its digits should be divisible by 3. 54,132 is an even number, so it is divisible by 2. 5 + 4 + 1 + 3 + 2 = 15, which is divisible by 3, so 54,132 is divisible by 3. Since 54,132 is divisible by both 2 and 3, it is divisible by 6.
102 is divisible by: 1 2 3 6 17 34 51 102.
For starters, the number 3 is divisible by 3 but not by 2. Next, 9, 27 etc. All the odd multiples of 3 are divisible by 3 but not 2. So there is an infinite number of numbers that are divisible by 3 and not 2.
Rule: If it is divisible by 2 and by 3Numbers are divisible by 6 if they are divisible by 3 and 2. Therefore, for example, since 18 is divisible by 3 and 2, it is also divisible by 6.The divisibility rule for 6 is, it can go into the number if 2 and 3 can also.