364 out of 365
367
You don't have to do anything. Everybody gets 52 weeks in 365 days. Plus an extra day!52 x 7 = 364
There is actually 364.something amount of days in an actual year and there is 365 days in a leap year A year is 365.24 days. This is calculated by the stars (sidereal year), we use a leap year to even out the minor discrepancies (2000 was not a leap year), but we are slightly off the sidereal year most of the time. The leap year has 366 days.
66,795 penniesOr 67,161 if the year includes 29th February.Of course, this assumes that I have not spent any pennies during the year. One method of calculating: # If there is an odd number of days, deduct 1, and halve the result.(365-1=364). By doing this we are temporarily removing the highest number '365' from the list of numbers, 1,2,3,4,5, etc. And you now have a list of all the numbers from 1 to 364.# Halve the result (half of 364 is 182) # Now think of your list as being pairs of numbers, the lowest numbers being linked with the highest numbers: i.e. 1+364(=365), 2+363(=365), 3+362(=365) etc. # You will have 182 pairs of numbers, each adding to 365, plus you will have one number over, the last 365. So you have 182+1(=183) x 365, which equals 66,795! If there is an even number of numbers, e.g. 366, (i.e. the number of days in a leap year) then the 183 'pairs' will be 1+366(=367), 2+365(=367) etc. 183 x 367 = 67,161!Or you could just add 366 to 66,795, which was the result for 365 days.
yes that is why each year has 365 days , actually practically speaking it some times has 364 or 364 one fourth days
364 out of 365
364 days, on leap yr: 365
367
Seven days in a week. So... 52(7) = 364.
You don't have to do anything. Everybody gets 52 weeks in 365 days. Plus an extra day!52 x 7 = 364
The Chichen Itza has 364 steps there is 91 steps on each side so, 91 x 4 ___ 364
There is actually 364.something amount of days in an actual year and there is 365 days in a leap year A year is 365.24 days. This is calculated by the stars (sidereal year), we use a leap year to even out the minor discrepancies (2000 was not a leap year), but we are slightly off the sidereal year most of the time. The leap year has 366 days.
364 days and 365 in a leep year
52 x 7(days in a week) = 364 + 1 = 365.
In Mathematica: Sum[((365!/(365 - k)!)) * k * StirlingS2[N, k], {k, 1, N}] / 365^N StirlingS2 is a Stirling Number of the Second Kind: http://en.wikipedia.org/wiki/Stirling_number_of_the_second_kind Or you could just do 365*(1- (364/365)^N) LOLZ.
Let us assume that there are exactly 365 days in a year and that birthdays are uniformly randomly distributed across those days. First, what is the probability that 2 randomly selected people have different birthdays? The second person's birthday can be any day except the first person's, so the probability is 364/365. What is the probability that 3 people will all have different birthdays? We already know that there is a 364/365 chance that the first two will have different birthdays. The third person must have a birthday that is different from the first two: the probability of this happening is 363/365. We need to multiply the probabilities since the events are independent; the answer for 3 people is thus 364/365 × 363/365. You should now be able to solve it for 4 people.