364 out of 365
367
You don't have to do anything. Everybody gets 52 weeks in 365 days. Plus an extra day!52 x 7 = 364
66,795 penniesOr 67,161 if the year includes 29th February.Of course, this assumes that I have not spent any pennies during the year. One method of calculating: # If there is an odd number of days, deduct 1, and halve the result.(365-1=364). By doing this we are temporarily removing the highest number '365' from the list of numbers, 1,2,3,4,5, etc. And you now have a list of all the numbers from 1 to 364.# Halve the result (half of 364 is 182) # Now think of your list as being pairs of numbers, the lowest numbers being linked with the highest numbers: i.e. 1+364(=365), 2+363(=365), 3+362(=365) etc. # You will have 182 pairs of numbers, each adding to 365, plus you will have one number over, the last 365. So you have 182+1(=183) x 365, which equals 66,795! If there is an even number of numbers, e.g. 366, (i.e. the number of days in a leap year) then the 183 'pairs' will be 1+366(=367), 2+365(=367) etc. 183 x 367 = 67,161!Or you could just add 366 to 66,795, which was the result for 365 days.
22% of 364 = 22% * 364 = 0.22 * 364 = 80.08
yes that is why each year has 365 days , actually practically speaking it some times has 364 or 364 one fourth days
364 out of 365
364 days, on leap yr: 365
367
Seven days in a week. So... 52(7) = 364.
You don't have to do anything. Everybody gets 52 weeks in 365 days. Plus an extra day!52 x 7 = 364
The Chichen Itza has 364 steps there is 91 steps on each side so, 91 x 4 ___ 364
364 days and 365 in a leep year
52 x 7(days in a week) = 364 + 1 = 365.
In Mathematica: Sum[((365!/(365 - k)!)) * k * StirlingS2[N, k], {k, 1, N}] / 365^N StirlingS2 is a Stirling Number of the Second Kind: http://en.wikipedia.org/wiki/Stirling_number_of_the_second_kind Or you could just do 365*(1- (364/365)^N) LOLZ.
Let us assume that there are exactly 365 days in a year and that birthdays are uniformly randomly distributed across those days. First, what is the probability that 2 randomly selected people have different birthdays? The second person's birthday can be any day except the first person's, so the probability is 364/365. What is the probability that 3 people will all have different birthdays? We already know that there is a 364/365 chance that the first two will have different birthdays. The third person must have a birthday that is different from the first two: the probability of this happening is 363/365. We need to multiply the probabilities since the events are independent; the answer for 3 people is thus 364/365 × 363/365. You should now be able to solve it for 4 people.
-365- IS 1973 Yamaha MX360. First 3 numbers tell me that, for example similar models of that time; the SC500 is 363 AND the MX250 is 364.