The question is based on the premise that It is not possible to simplify a radical without first factorising it. That is simply not true. Beginners may find it a useful step but that does not make it "important to always factor".
Simplifying radicals entails removing square factors of the radicand from under the radical. This can be done without factoring first.
Given that the radicand is part of the question, not part of the answer, you can make the radicand whatever you want it to be. However, in any given root sum, for example, sqrt(-4), if the index is even, such as it is in a square root sum, the answer will always be positive. If the index is odd, and the radicand is negative, the answer will also be negative.
To simplify a fraction, you find a number that can be divided by the fraction you are simplifying. sometimes this does not always work and the fraction can not be simplified.
Not at all important. Can always get back on the ride again later.
Always remember the turtles
The radicals must have the same indexes.Examples when radicals have index of 2.√3√7 = √(3*7) = √21√2√6 = √(2*6) = √12 = √(4*3) = √4√3 = 2√3We decided that i2 = -1, and i = √-1, to be able to find the square root of any negative radicand, which is not a real number.For example,√-4 = √(-1*4) = √-1√4 = 2i.√-45 = √-1√45 = i√(9*5) = i√9√5 = 3√5 iAlso, we allow ourselves to multiply the radicals of index 2, even though one or both of the radicals are negative.√-5√6 = = √(-5*6) = √-30 = i√30. But I do prefer to work in this way:√-5√6 = = √-1√5√6 = = i√(5*6) = i√30. This work will eliminate the common mistake that students always do when they multiply radicals of index 2 with both negative radicands.For example,√-2√-3 = √(-2*-3) = √6 (wrong, a positive real number!)√-2√-3 = (√-1√2)(√-1√3) = (i)(i)√(2*3) = i2√6 = -√6.Examples of division:√10/√2 = √(10/2) = √5√-15/√3 = (√-1√15)/√3 = i√(15/3) = i√5√21/√-7 = √21/(√-1√7) = (1/i)√(21/7) = (1/i)√3 but this result is not a representative of an imaginary number, as we decided it to be. So what to do in order to manipulate the result and write it as a proper imaginary number?Let 1 = -(-1) = -(i2), then I will have (1/i)√3 = (-i2/i)√3 = -i√3, the right answer.Conclusion: 1/i = -i.√-35/√-5 = (√-1√35)/(√-1√5) = (i/i)(√35/5) = √7, the right work.Even though, √-35/√-5 = (√(-35/-5) = √(35/5) = √7, it is wrong to work in that way.So we solved the problem of finding the square roots of negative numbers, by using the imaginary number i, and we also called it a complex number, and so we built a new set of numbers, the set of complex numbers. Actually, all numbers are invention of our mind, even though I would prefer not to say it for the number 1.
Given that the radicand is part of the question, not part of the answer, you can make the radicand whatever you want it to be. However, in any given root sum, for example, sqrt(-4), if the index is even, such as it is in a square root sum, the answer will always be positive. If the index is odd, and the radicand is negative, the answer will also be negative.
A
To simplify a fraction, you find a number that can be divided by the fraction you are simplifying. sometimes this does not always work and the fraction can not be simplified.
It depends on the circumstances. It is not always important
60/100 is the most direct representation. Simplifying down to 6/10 or 3/5. Percent means "per 100". So a percent is always that number divided by 100.
Initiator efficiency in free radical polymerization is typically low because not all initiator molecules generate active radicals that are capable of initiating polymerization reactions. This is due to side reactions such as termination or chain transfer processes that can reduce the number of active radicals available for polymerization. Additionally, some radicals may not efficiently propagate the polymerization due to their reactivity or stability.
The customer is always, always, right!
It is important to always be honest in your job.
It's possible to perform other operations first. But if you try it, there's a muchbigger chance that you'll get all tangled up and your result will be wrong.
I guess you mean "simplifying": Writing a term in a form that is deemed simpler (this is not always unique). For example, "4" is a simplification of "2+2", or "x^2" is a simplification of "(x-1)*(x+1)+1".
No. If you are self-important, that is a negative.
its important to have an objective because you always supposed have an question to answer