Choose a nonzero integer for n to show -n can be evaluated as a positive number?
I would do it that way.
The value of any nonzero number raised to the zero power will equal positive one (1).
It means that the number is an integer, AND that it is not zero.
To evaluate a nonzero number with a negative integer exponent, you can use the rule that states ( a^{-n} = \frac{1}{a^n} ), where ( a ) is the nonzero number and ( n ) is the positive integer. For example, ( 2^{-3} ) can be evaluated as ( \frac{1}{2^3} = \frac{1}{8} ). This method effectively converts the negative exponent into a positive one by taking the reciprocal of the base raised to the corresponding positive exponent.
The absolute value of a number is its distance from zero on the number line, so it is always non-negative. When you multiply two nonzero absolute values, you are essentially multiplying two non-negative numbers together. In multiplication, a positive number multiplied by a positive number always results in a positive number, hence the product of two nonzero absolute values is always positive.
The absolute value is always positive.
Positive
Yes. nonzero number: -4, -0.5, 5, pi, 30 absolute number: |-4| = 4 |-0.5| = 0.5 |5| = 5 |pi| = pi |30| = 30
The absolute value of a number equals the number itself if and only if the number is a positive real number (x >= 0 and does not include a nonzero imaginary component).
The absolute value of a number equals the number itself if and only if the number is a positive real number (x >= 0 and does not include a nonzero imaginary component).
The absolute value of a number equals the number itself if and only if the number is a positive real number (x >= 0 and does not include a nonzero imaginary component).
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Choose a nonzero integer for n to show -n can be evaluated as a positive number?
They are the positive and negative even numbers.
I would do it that way.
A mathematical element that when added to another numeral makes the same numeral