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If x2 is negative it will have a maximum value If x2 is positive it will have a minimum value
No. For 0 < x < 2, 2x is larger.
As long as the range of values for x stays within the set of real numbers, then:|x2| = x2As the square of a real number will always be positive anyway.If on the other hand, x belongs to the set of imaginary numbers, then:|x2| = -x2The reason for that is that in the case of imaginary numbers, x2 will give you a negative number. Its absolute value then would be the negative of that.And with complex numbers it's, well... complex:(ai + b)2 = -a2 + 2abi + b2So:|(ai + b)2| = a2 + 2abi + b2
Not necessarily. f(x) = -1-x2 is negative for any test value of x, it is asymptotically negative infinity, but it is NEVER zero.
-x times -x = x2 (negative multiplied with negative = positive) sqrt of x2 = x