If x2 is negative it will have a maximum value If x2 is positive it will have a minimum value
As long as the range of values for x stays within the set of real numbers, then:|x2| = x2As the square of a real number will always be positive anyway.If on the other hand, x belongs to the set of imaginary numbers, then:|x2| = -x2The reason for that is that in the case of imaginary numbers, x2 will give you a negative number. Its absolute value then would be the negative of that.And with complex numbers it's, well... complex:(ai + b)2 = -a2 + 2abi + b2So:|(ai + b)2| = a2 + 2abi + b2
No. For 0 < x < 2, 2x is larger.
Not necessarily. f(x) = -1-x2 is negative for any test value of x, it is asymptotically negative infinity, but it is NEVER zero.
-x times -x = x2 (negative multiplied with negative = positive) sqrt of x2 = x
If x2 is negative it will have a maximum value If x2 is positive it will have a minimum value
0
This equation is unsolvable as x2 cannot be a negative number as would be suggested by this equation. Any number, even a negative, multiplied by itself will always give a positive number but this equation leaves you with x2 = -48
As long as the range of values for x stays within the set of real numbers, then:|x2| = x2As the square of a real number will always be positive anyway.If on the other hand, x belongs to the set of imaginary numbers, then:|x2| = -x2The reason for that is that in the case of imaginary numbers, x2 will give you a negative number. Its absolute value then would be the negative of that.And with complex numbers it's, well... complex:(ai + b)2 = -a2 + 2abi + b2So:|(ai + b)2| = a2 + 2abi + b2
No. For 0 < x < 2, 2x is larger.
Not necessarily. f(x) = -1-x2 is negative for any test value of x, it is asymptotically negative infinity, but it is NEVER zero.
-x times -x = x2 (negative multiplied with negative = positive) sqrt of x2 = x
The answer would be 3x if 'X2' is '2x', but if 'X2' is x2, then the total answer would be x2 + x.
The Answer to x2-10x250 is negative 2500, also -2500.
no, its subtraction. if x2 is over x to the first power, the exponent at the higher value subtracts the x1. whether the x2 is above or below x1, x1 is always being subtrated from x2. X2 X(1) x __ OR __ = X or _ X(1) X2 1
It is a quadratic equation and the value of x is -7 or 6 x2 - 42 = (-x) x2 + x - 42 = 0 (x + 7) (x - 6) = 0
Any value to the zero power is 1. If an exponent is negative, you need to switch it from the numerator to the denominator or vice-versa. For example, x-2 is 1/x2.