it is a delicate system, so naturally it is delicate. sensitive, too, of course
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first factor (y-3)(y+1) so then u now have 2 problems y-3=0 so y=3 y+1=0 so y=-1 answer y=3 and -1
So substitute for y : x + 4x = 5 so 5x = 5, so x=1, y=4
2x1=1 so 1-Y=0 so Y=0, was this really a question?
A function is an equation that gives a unique answer. A relation does not. Example: y = 3x + 1 is a function. If I give you x, you can determine y. And that y is unique to that x. So if x = 1, you know y = 4. No other of x gives y = 4 as an answer. So y = 3x + 1 is a function. Example: y = 4x2. So if I give you x = 1, y = 4. But y = 4 if I also give you x = -1. So y = 4x2 is not a function, it is a relation.