That's not too hard to show. But first, you have to be comfortable enough with
calculus that the idea of a triple integral doesn't scare you. We're pretty sure
that the question can't be answered without spending a few minutes working
with one of them.
Surface area of sphere = 4r 4 xπ x r2 = 452.39 cm2 r2 = 452.39/(4) = 36.01831210191 cm2 r = sqrt(36.01831210191) = 6 cm(approximately) And volume is given by V = 4πr3 = 4 x π x 63/3 cm3 = 905.46912199289 cm3
The shape factor for a sphere is a dimensionless quantity that characterizes its geometry in relation to its volume and surface area. It is defined as the ratio of the surface area of the sphere to the square of its radius, which is given by the formula ( \text{Shape Factor} = \frac{4\pi r^2}{(2r)^2} = \frac{4\pi r^2}{4r^2} = \pi ). This indicates that the shape factor for a sphere is constant and equal to ( \pi ), reflecting its uniformity in all directions.
4r-48 = -44
s = -2 -4r
If you mean: 10+4r = 30 then it works out that r = 5
The surface charge density formula of a sphere is Q / 4r, where is the surface charge density, Q is the total charge on the sphere, and r is the radius of the sphere.
The area of a sphere is given by the formula A = 4πr² A sphere with radius r has an area = 4πr² A sphere with radius 2r has an area = 4π(2r)² = 4π.4r² = 16πr² The ratio of the larger sphere to the smaller = 16πr² : 4πr² = 4 : 1 If the area of the smaller sphere is 45 units then the area of the larger sphere is 45 x 4 = 180 units.
The formula for calculating the surface charge density of a sphere is: Q / 4r, where represents the surface charge density, Q is the total charge on the sphere, and r is the radius of the sphere.
Surface area of sphere = 4r 4 xπ x r2 = 452.39 cm2 r2 = 452.39/(4) = 36.01831210191 cm2 r = sqrt(36.01831210191) = 6 cm(approximately) And volume is given by V = 4πr3 = 4 x π x 63/3 cm3 = 905.46912199289 cm3
The shape factor for a sphere is a dimensionless quantity that characterizes its geometry in relation to its volume and surface area. It is defined as the ratio of the surface area of the sphere to the square of its radius, which is given by the formula ( \text{Shape Factor} = \frac{4\pi r^2}{(2r)^2} = \frac{4\pi r^2}{4r^2} = \pi ). This indicates that the shape factor for a sphere is constant and equal to ( \pi ), reflecting its uniformity in all directions.
-2=4r+s s=-4r-2 or s=-(4r+2)
4r-48 = -44
4r + 4 = 5r 4r - r = 3r 4r x r = 4r^2 4r/r = 4
If 36 = 4r, r = 9
It is 4r + 12s
4r + 13 = 57subtract 13 from both sides:4r + 13 - 13 = 57 -134r = 44divide both sides by 4 to solve for r:4r/4 = 44/4r = 11
64The formula to find the volume of a sphere is4/3 * pi * r3where r is the radius of the sphere. So if the radius is increased by a factor of 4, then the formula becomes4/3 * pi * (4r)3 = 4/3 * pi * 64r3showing that the volume increases by a factor of 64.