Let's look at an right isosceles triangle (where the base angles measure 45 degrees, and legs are congruent). So that,
tan 45 degrees = leg/leg = 1
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β 14y ago1
tan 45° = 1
45 degrees
0 is your answer tan(45)=1 and arccos(1)=0
If y = 2x+1 is a tangent line to the circle 5y^2 +5x^2 = 1 then the point of contact is at (-2/5, 1/5) because it has equal roots
Tangent is determined by the ratio of the side opposite the angle over the one adjacent to it. In a 45-45-90 triangle, the ratio of these sides is 1. This is because the side opposite one of the 45 degree angles is adjacent to the other, and vise versa.
The angle you seek is 45 degrees. The angle whose tangent is 1 can be written arctan(1) = 45 degrees.
Yes. The tan of 45 degrees is 1.
Cotangent 32 equals tangent 0.031
45 degrees
If y = 2x+1 is a tangent line to the circle 5y^2 +5x^2 = 1 then the point of contact is at (-2/5, 1/5) because it has equal roots
opposite/ adjacent
If: y = kx+1 is a tangent to the curve y^2 = 8x Then k must equal 2 for the discriminant to equal zero when the given equations are merged together to equal zero.
45 miles would be 9 inches if 1 inch equals to 5 miles.
45
in a right trianlge the tangent is the ratio of Opposite/Adjacentcosine is Adjacent/Hypotenusesine is Opposite/Hypotenuse
Sine of the angle to its cosine.