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Example 7/9 - 2/5 1. Make denominators the same (they're the bottom bits) 7/9*5/5 = 35/45 2/5*9/9 = 18/45 2. Now they're the same 35/45 - 18/45 = 17/45
Assuming that 0.644444444 is a recurring decimal 0.6444... = 29/45 The steps in working it out. Let x = 0.0444...., then 100x = 4.4444.... => 100x - x = 4.4 => 99x = 4.4 => x = 4.4/99 = 44/990 = 4/90 = 2/45 So 0.6444... = 0.6 + 0.0444... = 3/5 + 2/45 = 27/45 + 2/45 = 29/45
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Find the repeating bit. i.e. In 0.45454545 the repeating bit is 45 If it has 2 digits divide it by 99, if it has three digits divide by 999 and so on So with 0.45454545, we divide 45 by 99 Cancell down this fraction to get the final answer 45/99=5/11 so 0.45454545 = 45/99= 5/11
Follow these steps 1. Using distributive property, first, distribute 36 into 4n and 45 so : 36x4n - 36x5 that becomes (144n-180)45 2. Distribute 45 to 144n and 180 so: 45x144n- 45x180 that becomes 6480n-8100 3. SImply by dividing by 1620 4n-5 so your final answer is 4n-5