The expression -x² is always negative for any nonzero value of x because squaring a nonzero number (whether positive or negative) results in a positive value. Thus, when you take the negative of that positive value, you end up with a negative result. For example, if x = 2, then -x² = -4, and if x = -2, then -x² = -4 as well. In both cases, -x² is negative.
The premise of your question is false: -x³ is positive if x is negative.
The value of any nonzero number raised to the zero power will equal positive one (1).
The sum of a number and its negative (additive inverse) is zero. For any nonzero value n, n + (-n) = 0
Adding zero
The premise of your question is false: -x³ is positive if x is negative.
The operation that will always have the result in value of 1 for any nonzero number is Inverse Operation of Multipication.
The value of any nonzero number raised to the zero power will equal positive one (1).
The sum of a number and its negative (additive inverse) is zero. For any nonzero value n, n + (-n) = 0
multiplying by zero
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Adding zero
It is always 1
== == The fact is - any nonzero number raised to 0 is always 1. the reason is: suppose a is nonzero. Then by the quotient rule of indices, am/an = am - n Taking m = n we come up with am - m = am/am , which is 1 in view of a nonzero.
Not if the original number is positive, otherwise yes.
Multiplication by zero is one such operation.
No. The absolute value is the distance a number is from zero. It is always represented by a positive number. The absolute value of any positive number and its negative counterpart is the same.