The min and max is when the first derivative , or slope at any point, is zero. For f of x = 2x first derivative is 2, so this is constant slope with no min or max as this is not zero; min is thus negative infinity and max is infinity
the sixth thermometer
Not necessarily.
You take the integral of the sin function, -cos, and plug in the highest and lowest values. Then subtract the latter from the former. so if "min" is the low end of the series, and "max" is the high end of the series, the answer is -cos(max) - (-cos(min)), or cos(min) - cos(max).
solved examples of normalization
=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)
Steps to perform MaxMin on a data set (2,4,6,3,8,1,9,7) are:(2,4,6,3) (8,1,9,7)((2,4)(6,3)) ((8,1)(9,7))In sublist (4,6), max is 6 and min is 4. In sublist (8,9), max is 9 and min is 8.Comparing max and min values of sublist (2,4) and sublist (6,3), value of max is 6 and min is 2.Therefore, for sublist (2,4,6,3) max is 6 and min is 2.Similarly, comparing max and min values of sublist (8,1) and sublist (9,7), value of max is 9 and min is 1.Therefore, for sublist (8,1,9,7) max is 9 and min is 1.Finally, comparing max and min values of sublist (2,4,6,3) and sublist (8,1,9,7), value of max is 9 and min is 1. Steps to perform MaxMin on a data set (2,4,6,3,8,1,9,7) are:(2,4,6,3) (8,1,9,7)((2,4)(6,3)) ((8,1)(9,7))In sublist (4,6), max is 6 and min is 4. In sublist (8,9), max is 9 and min is 8.Comparing max and min values of sublist (2,4) and sublist (6,3), value of max is 6 and min is 2.Therefore, for sublist (2,4,6,3) max is 6 and min is 2.Similarly, comparing max and min values of sublist (8,1) and sublist (9,7), value of max is 9 and min is 1.Therefore, for sublist (8,1,9,7) max is 9 and min is 1.Finally, comparing max and min values of sublist (2,4,6,3) and sublist (8,1,9,7), value of max is 9 and min is 1. Steps to perform MaxMin on a data set (2,4,6,3,8,1,9,7) are:(2,4,6,3) (8,1,9,7)((2,4)(6,3)) ((8,1)(9,7))In sublist (4,6), max is 6 and min is 4. In sublist (8,9), max is 9 and min is 8.Comparing max and min values of sublist (2,4) and sublist (6,3), value of max is 6 and min is 2.Therefore, for sublist (2,4,6,3) max is 6 and min is 2.Similarly, comparing max and min values of sublist (8,1) and sublist (9,7), value of max is 9 and min is 1.Therefore, for sublist (8,1,9,7) max is 9 and min is 1.Finally, comparing max and min values of sublist (2,4,6,3) and sublist (8,1,9,7), value of max is 9 and min is 1. sonika aggarwal GNIIT
The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)
int sum (int min, int max) {return (max-min+1)*(max+min)/2;}
int a, b, c, d, max, min; scanf("%d%d%d%d",&a, &b, &c, &d); (a>b)?(max=a,min=b):(max=b,min=a); (c>d)?(a=c,b=d):(a=d,b=c); max=(a>max)?a:max; min=(b<min)?b:min; printf("%d %d\n", max, min);
min: 0.5 KVA MAX: 1.5 KVA
Usually, max 212 F and min 32 F It depends on for what the thermometer will be used. My greenhouse min/max thermometer has a min of -40°F and a max of 120°F A (non-digital) clinical thermometer has a min of 94°F and a max of 108°F A cook's (sugar/jam) thermometer has a min of 100°F and a max of 400°F
The min and max temp of mars i 1,299 degrees celcius and -1,000,000 degrees celcius
Min-Max normalization is the process of taking data measured in its engineering units (for example: miles per hour or degrees C) and transforming it to a value between 0.0 and 1.0. The lowest (min) value is set to 0.0 and the highest (max) value is set to 1.0. This provides an easy way to compare values that are measured using different scales (for example degrees Celsius and degrees Fahrenheit) or different units of measure (speed and distance). The normalized value is defined as: (the value - the minimum) / (the range of values). As an example, consider a temperature reading with values 20, 24, 26, 27, 30. The minimum value is 20. The maximum values is 30. The data has a range of 10 degrees. For a temperature reading of 26, the normalized value is 0.6. (26 - 20) / 10 = 0.6.
Min-Max normalization is the process of taking data measured in its engineering units (for example: miles per hour or degrees C) and transforming it to a value between 0.0 and 1.0. The lowest (min) value is set to 0.0 and the highest (max) value is set to 1.0. This provides an easy way to compare values that are measured using different scales (for example degrees Celsius and degrees Fahrenheit) or different units of measure (speed and distance). The normalized value is defined as: (the value - the minimum) / (the range of values). As an example, consider a temperature reading with values 20, 24, 26, 27, 30. The minimum value is 20. The maximum values is 30. The data has a range of 10 degrees. For a temperature reading of 26, the normalized value is 0.6. (26 - 20) / 10 = 0.6.
#include<stdio.h> int main() { int a[20],min,max; int n; printf("\nEnter the num of elements: "); scanf("%d",&n); printf("Enter the elements\n"); for(int i=0;i<n;i++) { scanf("%d",&a[i]); if(i==0) { min=max=a[i]; } if(a[i]<min) min=a[i]; else if(a[i]>max) max=a[i]; } printf("The largest element is %d. The smallest element is %d.", max, min); }
You can use the SEQUENCE function in Excel to create a series of numbers from max to min or min to max. For example, to create a series from 10 to 1 in descending order, you could use =SEQUENCE(10,1,-1). This formula generates a range of numbers from 10 to 1 in descending order.