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as we define mole to be mass of the solute divided by molecular mass of the solute so all the solutes are taken in the solid form not in the liquid like we take 1L in molarity,so solids are generally independent of temp thats why both molality and mole fraction are independent of temperature

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Why mole fraction does not dependend upon temperature?

because mole fraction doesnot depend on volume


State relation between mole fraction and Volume fraction?

For Ideal gases, mole fraction=volume fraction


When can volume fraction be equal to mole fraction?

The volume fraction of a substance is equal to the mole fraction for ideal gas mixture


What is the approximate mole fraction of nitrogen and oxygen in the atmosphere combined?

The approximate mole fraction of nitrogen in the atmosphere is about 0.7808, and the approximate mole fraction of oxygen is about 0.2095. When combined, the mole fraction of nitrogen and oxygen in the atmosphere is approximately 0.9903.


What is the mole fraction of oxygen in a gas mixture that is 37 percent oxygen and 63 percent nitrogen in volume?

To find the mole fraction of oxygen, first convert the percentages to fractions: 37% oxygen is 0.37 and 63% nitrogen is 0.63. Since the total mole fraction in a mixture is 1, the mole fraction of oxygen would be 0.37/(0.37 + 0.63) = 0.37/1 = 0.37. Therefore, the mole fraction of oxygen in the gas mixture is 0.37.


How can one calculate the mole fraction from pressure in a given system?

To calculate the mole fraction from pressure in a given system, you can use the formula: Mole fraction Partial pressure of the component / Total pressure of the system Simply divide the partial pressure of the component by the total pressure of the system to find the mole fraction.


What is the mole fraction of oxygen gas in air?

The mole fraction of oxygen gas in air is approximately 0.21. This means that out of every 1 mole of air, 0.21 moles are oxygen gas molecules.


What is the vapor pressure of a water solution in which the molefraction of HgCl2 is 0.163 at 25C?

To calculate the vapor pressure of the water solution with a mole fraction of HgCl2 of 0.163 at 25°C, you would need to use Raoult's Law. The vapor pressure of the solution would be equal to the mole fraction of water multiplied by the vapor pressure of pure water at that temperature. The vapor pressure of HgCl2 can be ignored since its mole fraction is given.


What is the relationship between the mole fraction and molality in a solution?

The relationship between mole fraction and molality in a solution is that the mole fraction is the ratio of moles of a component to the total moles in the solution, while molality is the concentration of a component in moles per kilogram of solvent. The mole fraction can be calculated using the molality and the molar mass of the solvent.


What is the mole fraction of solute and solvent is equal to?

When the mole fraction of solute and solvent is equal, it means that both components are present in equal amounts in the solution. This would correspond to a mole fraction of 0.5 for both the solute and solvent.


How can one determine the mole fraction from vapor pressure?

To determine the mole fraction from vapor pressure, you can use Raoult's Law. This law states that the vapor pressure of a solution is directly proportional to the mole fraction of the solvent in the solution. By measuring the vapor pressure of the solution and knowing the vapor pressure of the pure solvent, you can calculate the mole fraction of the solvent in the solution using the formula: Mole fraction of solvent Vapor pressure of solution / Vapor pressure of pure solvent


What is the relationship between mole fraction and mass fraction in a given mixture?

The relationship between mole fraction and mass fraction in a mixture is that the mole fraction of a component is equal to its mass fraction divided by its molar mass, multiplied by the total mass of the mixture. This relationship helps in understanding the proportion of each component in the mixture based on their masses and molar masses.