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How do you find p-values?
Using a statistical software package is great!Otherwise, it HIGHLY depends on what you are finding the P-value for! This information would have been helpful.If you are looking for p-values based on something using the normal distribution, this is simple. Calculate the z-score of your observed result (be it individual observation if the population is normally distributed, or sample observation). Then do a reverse lookup in a z table to find the corresponding 4 digit decimal.If using a symmetric z table, you will need to subtract that decimal from .5, then double the result if using a 2-tail test. Don't double if a 1-tail test.If using a cumulative z table, you will need to look up the result for the negative signed z-score; double your result if 2-tailed, don't double if one-tailed.Next time, be more specific, and the answer will be!
Can you solve the roman numeral equation of L minus some unknown equals C detailing your workings?
In Roman numerals L and C are 50 and 100 respectively. So substitute 50 and 100 into the equation and let the unknown be called z. 50-z = 100 -z = 100-50 -z = 50 --z = -50 Solution: z = -50 Substituting -50 into the equation: 50--50 = 100 or L--L = C. Remember that in maths a double minus sign before a number changes that number into a plus number. Check it out on your calculator. David Gambell, Merseyside, England.
How do you find the number z such that 93 percent of all observations from a standard Normal distribution are greater than z?
The tables for Z-scores are given in the form of P = Prob(Z < z) for various value of P and z. Since Prob(Z > z) = 0.93 > 0.5, then by symmetry, z < 0. So suppose z = -a where a > 0 Now Prob(Z > -a) = 0.93 is the same as Prob(Z < a) = 0.93 [because the standard Normal is symmetric]. therefore, from the tables, a = 1.4758 (approx) and so z = -1.4758 (approx).
What is one-third of z?
z divided by 3
