Because not to do so would change the relationship between them 3.45/12.3 = 345/1230 = 0.2805 (approx)
If you multiplied the dividend by 100 and the divisor by ten (doing just enoguh to remove the decimal places) then the relationship (the ratio) changes 345/ 123 = 2.8049 (approx)
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If you are a beginner and not comfortable doing divisions when either the numerator or particularly the denominator are decimal fractions, then it is useful to multiply them both by the same power of 10 to get rid of the decimal fractions.
Some people do that so that the divisor becomes an integer under the impression that dividing by a whole number is, in some way, easier than dividing by a decimal.
Multiplying both the dividend and divisor by a power of 10 is done to convert the decimal divisor into a whole number. This allows us to perform the division operation using whole numbers, making it easier to calculate. It maintains the overall value of the division while simplifying the computation.
You do not need to, but if you must do the following: if the divisor has n digits after the decimal point then multiply by 10n.
Multiply the divisor by a power of 10 to make it a whole number.
If you are a beginner and not comfortable doing divisions when either the numerator or particularly the denominator are decimal fractions, then it is useful to multiply them both by the same power of 10 to get rid of the decimal fractions.
Some people do that so that the divisor becomes an integer under the impression that dividing by a whole number is, in some way, easier than dividing by a decimal.
Multiplying both the dividend and divisor by a power of 10 is done to convert the decimal divisor into a whole number. This allows us to perform the division operation using whole numbers, making it easier to calculate. It maintains the overall value of the division while simplifying the computation.
0.3413
There are two main methods:Euclid's methodChoose one of the numbers to be the dividend of a division and the other to be the divisor.Perform the divisionIgnore the quotient and keep the remainderIf the remainder is zero, the last divisor is the GCDReplace the dividend by the divisorReplace the divisor by the last remainderRepeat from step 2.It doesn't matter which number is the dividend and which is the divisor of the first division, but if the larger is chosen as the divisor, the first run through the steps above will swap the two over so that the larger becomes the dividend and the smaller the divisor - it is better to choose the larger as the dividend in the first place. Prime factorisationExpress the numbers in their prime factorisations in power format. Multiply the common primes to their lowest power together to get the GCD.The first is limited to two numbers, but the latter can be used to find the gcd of any number of numbers.Examples:GCD of 500 and 240:Euclid's method:500 ÷ 240 = 2 r 20 240 ÷ 20 = 6 r 0gcd = 20Prime factorisation:500 = 22 x 53 240 = 24 x 3 x 5gcd = 22 x 5 = 20
You do not need to, but if you must do the following: if the divisor has n digits after the decimal point then multiply by 10n.
37.5
Multiply the divisor by a power of 10 to make it a whole number.
0.0
0.7086
By (long) division:. . . . . . . . . . .2x2 - 7x . + 2. . . . . ----------------------x + 2 | 2x3 - 3x2 - 12x + 4. . . . . .2x3 + 4x2. . . . . .-----------. . . . . . . . . - 7x2 - 12x. . . . . . . . . - 7x2 - 14x. . . . . . . . . ------------. . . . . . . . . . . . . . . . 2x + 4. . . . . . . . . . . . . . . . 2x + 4. . . . . . . . . . . . . . . . -------. . . . . . . . . . . . . . . . . . . . .0. . . . . . . . . . . . . . . . ====(the "dot-spaces" are used to hold the characters in the right place of the division - they should be treated as blank)Thus since(x + 2)(2x2 - 7x + 2) = 2x3 - 3x2 - 12x + 4(x + 2) is a factor of 2x3 - 3x2 - 12x + 4In the division:the first term of the divisor (x) is compared with the highest power of x remaining in the dividend to find the next term of the quotient;the whole divisor is multiplied by this;then subtracted from the dividend;Steps 1-3 are repeated until there is no first term of the divisor (x) in the dividend.If the dividend is '0' (ie the last multiplication resulted in what was remaining in the dividend) then the divisor is a factor of the original dividend); otherwise it is not a factor.
Dividend: 6x^3+29x^2-40x-42 Divisor: 6x+5 Quotient: x^2+4x-10 Remainder: 8