That's an extraneous solution. You need to check for these when algebraically solving equations, especially when you take both sides of an equation to a power.
Checking your solution in the original equation is always a good idea,simply to determine whether or not you made a mistake.If your solution doesn't make the original equation true, then it's wrong.
Plug your answer back into the original equation.Example:3x+15=21x=23(2)+15=21
Put the values that you find (as the solution) back into one (or more) of the original equations and evaluate them. If they remain true then the solution checks out. If one equation does not contain all the variables involved in the system, you may have to repeat with another of the original equations.
insert the answer in the equation, replacing the variable, and see if it still makes sense.
plug your solution back into the original equation and work it out again
That's an extraneous solution. You need to check for these when algebraically solving equations, especially when you take both sides of an equation to a power.
If you mean for a math problem, after coming up with a solution you should usually check the solution in the original equation, to be safe.
If you found the value of x that is a solution to an equation, you want to substitute that value back into the original equation, to check that it indeed satisfies the equation. If it does not satisfy the equation, then you made an error in your calculations, and you need to rework the problem.
Checking your solution in the original equation is always a good idea,simply to determine whether or not you made a mistake.If your solution doesn't make the original equation true, then it's wrong.
An "extraneous solution" is not a characteristic of an equation, but has to do with the methods used to solve it. Typically, if you square both sides of the equation, and solve the resulting equation, you might get additional solutions that are not part of the original equation. Just do this, and check each of the solutions, whether it satisfies the original equation. If one of them doesn't, it is an "extraneous" solution introduced by the squaring.
how can the reflexive property be applied to check the accuracy of a solution to equation?
By substitution.
Plug your answer back into the original equation.Example:3x+15=21x=23(2)+15=21
Put the values that you find (as the solution) back into one (or more) of the original equations and evaluate them. If they remain true then the solution checks out. If one equation does not contain all the variables involved in the system, you may have to repeat with another of the original equations.
It really depends on the type of equation, but in the simpler cases - those that you are likely to encounter in high school algebra - you will usually need to replace the purported solution into the original equation, then simplify the equation as appropriate. If this results in a true statement (for example, "5 = 5"), then the solution is correct; if you get a false statement (for example, "1 = 0"), then the purported solution is not correct.
Solution. A solution of an equation is a number that satisfy the equation. This means that if you replace this number on the equation and check it, the equation will be true. When you solve an equation you can find some roots, but not all of them satisfy the equation. Thus always check your answers after resolving your equation, and eliminate as solution the answers that don't make the equation true or undefined.