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If you are talking about the 6th numerical row (1 5 10 10 5 1, technically 5th row because Pascal's triangle starts with the 0th row), it does not appear to be a multiple of 11, but after regrouping or simplifying, it is. We have 1 5 10 10 5 1 which is equivalent to 105 + 5*104 + 10*103 + 10*102 + 5*101 + 1 = 161051. This is equal to 115.

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Q: Why sixth row in Pascals triangle not and exponent of 11?
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