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If you are talking about the 6th numerical row (1 5 10 10 5 1, technically 5th row because Pascal's triangle starts with the 0th row), it does not appear to be a multiple of 11, but after regrouping or simplifying, it is. We have 1 5 10 10 5 1 which is equivalent to 105 + 5*104 + 10*103 + 10*102 + 5*101 + 1 = 161051. This is equal to 115.
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What is the 5th row on pascals triangle?
1,4,6,4,1
What is the sum of the 4 th row of pascals triangle?
The sum is 24 = 16
How is the pascal triangle and the binomial expansion related?
If the top row of Pascal's triangle is "1 1", then the nth row of Pascals triangle consists of the coefficients of x in the expansion of (1 + x)n.
What numbers are in the fifth row of pascals triangle?
1 5 10 10 5 1
What are the third and sixth entries in the row 12 of Pascals triangle?
To find a specific number in Pascal's triangle, use the formula n!/r!(n-r)! Where n is the row number (starting at 0) and r is the row element (starting at 0) So for the 3rd entry of the 12th row we would put in the following numbers: 11!/2!(11-2)! which equals 55 Do the same for the 6th entry of the 12th row and you get 462.
