Why not? The statement is trivially true, meaning it holds for all values of x.
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Double first equation: 10x + 2y = 10Subtract second equation: 7x = 7x = 1, y = 0
It is an equation and the value of x is 2
7x - 3 = 3 Subtract 3 from both sides: 7x - 6 = 0 So a = 7 and b = -6
x2+7x+3 = 0 Using the quadratic equation formula the solutions are:- x = -6.541381265 or x = -0.4586187349
Given 6x + (7x-8) = -5 6x + 7x - 8 = -5 ==> 13x = 3 therefore, x = 3/13