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Does intil have 1l or 2 l's?
I tink 2 l's
If the perimeter of a rectangle is 30m and the length of the rectangle is less than twice the width what is the lenght?
2*L + 2*W = 30m L<2*W So, 2*L + L < 30m L < 10m
How do you find the perimeter of a right isosceles triangle if you already know its area?
Suppose the lengths of the short sides of the triangle are L Then, by Pythagoras, the third side is sqrt(L2 + L2) = sqrt(2L2) = L*sqrt(2) So the perimeter is L+L+L*sqrt(2) = L*[2+sqrt(2)] Also, if the length of the two short sides is L, the area, A, is 0.5*L*L that is A = 0.5*L2 or L = sqrt(2*A) Combining the two equations, given A, he perimeter is sqrt(2*A)*[2+sqrt(2)] =sqrt(A)*[2*sqrt(2)+2] or 2*sqrt(A)*[1+sqrt(2)] Hope that is correct and helps.
If A (7 9) and B (3 12) what is the length of line ab?
Use Pythagoras l^2 = a^2 + b^2 A = (7,9) & B= (3,12) NB 'A' & 'B' are NOT the same as 'a' & 'b' . Each is just a label, Hence l^2 = (7-3)^2 + (9 - 12)^2 l^2 = 4^2 + (-3)^2 l^2 = 16 + 9 l^2 = 25 l = sqrt(25) l = 5 The answer!!!!!
The perimeter of a rectangle is 54 in the width is 5 in less than the length find the length and width?
L*2+w*2=54 (1) l*2+(l-5)*2=54 l*4 - 10 = 54 l=16 (1) ---> 16*2+w*2=54 w=11
