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Use Pythagoras

l^2 = a^2 + b^2

A = (7,9)

& B= (3,12)

NB 'A' & 'B' are NOT the same as 'a' & 'b' . Each is just a label,

Hence l^2 = (7-3)^2 + (9 - 12)^2

l^2 = 4^2 + (-3)^2

l^2 = 16 + 9

l^2 = 25

l = sqrt(25)

l = 5 The answer!!!!!

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lenpollock

Lvl 16
1y ago

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If A (0 0) and B (6 3) what is the length of AB?

To find the length of the line segment AB, you can use the distance formula: ( AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). For points A(0, 0) and B(6, 3), the calculation is ( AB = \sqrt{(6 - 0)^2 + (3 - 0)^2} = \sqrt{6^2 + 3^2} = \sqrt{36 + 9} = \sqrt{45} = 3\sqrt{5} ). Therefore, the length of AB is ( 3\sqrt{5} ).


If a -1-3 and b 11-8 what is the length of AB?

To find the length of segment AB, we can use the distance formula. Given points A (-1, 3) and B (11, -8), the length of AB is calculated as follows: [ AB = \sqrt{(11 - (-1))^2 + (-8 - 3)^2} = \sqrt{(11 + 1)^2 + (-11)^2} = \sqrt{12^2 + (-11)^2} = \sqrt{144 + 121} = \sqrt{265} \approx 16.28. ] Therefore, the length of AB is approximately 16.28 units.


What is the length of AB 3x?

The length of AB is given as 3x, which means that it is a variable length dependent on the value of x. To determine the actual length, you would need to know the value of x. Once x is specified, you can multiply it by 3 to find the length of AB.


If AB contains the points 6 -2 and -3 16 what is the slope of a line perpendicular to AB?

0.5


Is A(-1-3) and B(11-8) what is the length of ab?

To find the length of segment AB between points A(-1, -3) and B(11, -8), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting the coordinates, we have: [ d = \sqrt{(11 - (-1))^2 + (-8 - (-3))^2} = \sqrt{(12)^2 + (-5)^2} = \sqrt{144 + 25} = \sqrt{169} = 13. ] Thus, the length of AB is 13 units.