Use Pythagoras
l^2 = a^2 + b^2
A = (7,9)
& B= (3,12)
NB 'A' & 'B' are NOT the same as 'a' & 'b' . Each is just a label,
Hence l^2 = (7-3)^2 + (9 - 12)^2
l^2 = 4^2 + (-3)^2
l^2 = 16 + 9
l^2 = 25
l = sqrt(25)
l = 5 The answer!!!!!
To find the length of the line segment AB, you can use the distance formula: ( AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). For points A(0, 0) and B(6, 3), the calculation is ( AB = \sqrt{(6 - 0)^2 + (3 - 0)^2} = \sqrt{6^2 + 3^2} = \sqrt{36 + 9} = \sqrt{45} = 3\sqrt{5} ). Therefore, the length of AB is ( 3\sqrt{5} ).
To find the length of segment AB, we can use the distance formula. Given points A (-1, 3) and B (11, -8), the length of AB is calculated as follows: [ AB = \sqrt{(11 - (-1))^2 + (-8 - 3)^2} = \sqrt{(11 + 1)^2 + (-11)^2} = \sqrt{12^2 + (-11)^2} = \sqrt{144 + 121} = \sqrt{265} \approx 16.28. ] Therefore, the length of AB is approximately 16.28 units.
The length of AB is given as 3x, which means that it is a variable length dependent on the value of x. To determine the actual length, you would need to know the value of x. Once x is specified, you can multiply it by 3 to find the length of AB.
0.5
To find the length of segment AB between points A(-1, -3) and B(11, -8), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting the coordinates, we have: [ d = \sqrt{(11 - (-1))^2 + (-8 - (-3))^2} = \sqrt{(12)^2 + (-5)^2} = \sqrt{144 + 25} = \sqrt{169} = 13. ] Thus, the length of AB is 13 units.
Using the distance formula the length of ab is 5 units
Using the distance formula the length of ab is 5 units
3
The length of AB is given as 3x, which means that it is a variable length dependent on the value of x. To determine the actual length, you would need to know the value of x. Once x is specified, you can multiply it by 3 to find the length of AB.
-2
We suspect that 'A' is not equal to 7 9, but that (7, 9) arethe coordinates of 'A'. Same for 'B'.If that's true, then the two points are 5 units apart.
-1/2 or -0.50
The length is 3*sqrt(5) = 6.7082, approx.
h
0.5
36/√3
If you mean endpoints of (-1, -3) and (11, -8) then the length works out as 13