If you mean six consecutive INTEGERS, then the answer is Yes.
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Yes. Let the two consecutive odd numbers be (2n - 1) and (2n + 1) for all values of integer n (ie n ∈ ℤ) Then their sum is: sum = (2n - 1) + (2n + 1) = 2n + 2n = (2 + 2)n = 4n = a multiple of 4, so is divisible by 4.
The sum is always 3 more than (triple the smallest number).
If n is the first number, n + n + 1 + n + 2 + n + 3 will be the sum, which is 4n + 6. 4n is always even, and 6 is even. Therefore, the sum of four consecutive numbers is always even.
A multiple of 3 Also a multiple of 6.
ODD NUMBERS. If you take two consecutive whole (non zero) numbers then one will be an odd number and the other will be an even number. The sum of an odd number and an even number is always an odd number.