#include<stdio.h>
#define MAXVAL 1000
void sort1(int a[],int n);
void median(int a[],int n);
void mode(int a[],int n);
int main()
{
int n;
int arr[MAXVAL];
int i;
printf("Enter the number of elements:");
scanf("%d",&n);
printf("Enter the values:");
for(i=0;i<n;i++)
{
printf("a[%d]=",i);
scanf("%d",&arr[i]);
}
sort1(arr,n);
median(arr,n);
mode(arr,n);
}
void sort1(int a[],int n)
{
int i;
int j;
int temp;
for(i=0;i<n;i++)
{
for(j=i;j<n;j++)
{
if(a[i]>a[j])
{
temp=a[i];
a[i]=a[j];
a[j]=temp;
}
}
}
}
void median(int a[],int n)
{
int median;
int mid;
if((n%2)==0)
{
mid=n/2;
median=(a[mid-1]+a[mid])/2;
}
else
{
mid=(n+1)/2;
median=a[mid-1];
}
printf("The median is:%d\n",median);
}
void mode(int a[],int n)
{
int i;
int count1[MAXVAL];
for(i=0;i<n;i++)
{
count1[i]=0;
}
for(i=0;i<n;i++)
{
count1[a[i]]++;
}
i--;
int mode=count1[0];
int j;
int k;
int flag=0;
for(j=0;j<=a[i];j++)
{
if(count1[j]>count1[mode])
mode=j;
}
for(j=0;j<=a[i];j++)
{
for(k=j+1;k<=a[i];k++)
{
if(count1[j]=count1[k] && count1[j]>count1[mode])
{
flag=1;
}
}
}
if(flag==1)
{
printf("Mode cannot be calculated");
}
else
printf("the Mode is:%d",mode);
}
try this---> http://c-pgms.blogspot.com/2008/08/program-to-find-meanmedianand-mode_22.html
The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5
The mean is better than the median when there are outliers.
median is the middle number mean is average mode is most median is middle range is high - low
the median and mode are but the mean is not
Yes. If the lower values tend to be farther below the median than the highest values are above the median, the mean is smaller than the median. why are write wrong
The mean deviation from the median is equal to the mean minus the median.
try this---> http://c-pgms.blogspot.com/2008/08/program-to-find-meanmedianand-mode_22.html
The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5
who discovered mean median and mode
Mean, Median and Mode. They are three kinds of averages.
Mean is the average, and median is the middle number.
You can estimate the median and the mean.
The mean is better than the median when there are outliers.
To find the median of a set of numbers write them in order, then: * if there are an odd number of numbers then the median is the number in the middle * otherwise there are an even number of numbers and the median is the mean average of the two numbers in the middle. With 4 numbers there is an even number of numbers, so the median is the mean average of the 2nd and 3rd numbers when they are sorted into order. Example: Find median of {3, 9, 4, 5} Ordered → {3, 4, 5, 9} → median = mean_average(4, 5) = (4 + 5) ÷ 2 = 4.5
The mean and the median are both involved with a set of numbers. The mean refers to the average of the numbers. The median refers to the middle number of the numbers
median = 8 mean = 7 mean < median.