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A simple way to do this is to write something that will produce division by zero at those points. Something like 1 / (x-6)(x-3). You can put anything you like into the numerator, instead of the 1.

Q: Write an expression for which 6 and 3 are excluded for the domain?

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x/3

3 - k

3+c

Three and eight times a number.

add 3 to a number a number plus 3 the sum of a number and 3 3 more than a number a number increased by 3

Related questions

It is not possible to answer the question since no equation is given in the question: only an expression.

x/3

3 - k

Re-write it with a root. If the power of the expression is less than 1, for example x1/3, the expression could be rewritten as cube root of x.

A fraction is a division expression. 3/4 = three divided by four

Here is a non-conventional answer: -3 / 3 - 3 + 33 = 29 Use five 3's to write an expression whose value equals 29?

3+c

Three and eight times a number.

6•2+6•3

33 + (3 + 3)/3

You can write 24 multiplied by 3 is, 3(24)

add 3 to a number a number plus 3 the sum of a number and 3 3 more than a number a number increased by 3